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3 years ago

Explain how to write the explicit rule for the arithmetic sequence from the given information

Mathematics

1 answer:

Alexxx [7]3 years ago

6 0

The rule is to put them in order

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Tony Owens a special pet store that sells only snacks and elephants currently he has a total of 11 snacks and elephants in stock

bagirrra123 [75]

Answer: There are 8 snake and 3 elephants.

Step-by-step explanation:

Let x= Number of snakes

y= Number of elephants

We know that , snake has no legs elephant has 4 legs.

Then, Total animals = x+y=11 (i)

Total legs = 4y = 12

⇒ y=3 .. (ii)[divide both sides by 4]

Substitute value of y from (ii) in (i) , we get

$x+3=11\Rightarrow\ x=8$

Hence, there are 8 snake and 3 elephants.

3 0

2 years ago

A customer opens a checking account and a savings account at a bank. They will deposit a maximum of $600, some in the checking a

bagirrra123 [75]

Answer:

x +y $\leq \\$ 600

Step-by-step explanation:

8 0

2 years ago

colleen truman earns aa 4.5% commission on all sales. in june, her sales totaled $40,000. how much did she earn in commission?

prisoha [69]

She earned 1,800$ in commission. Total=40,000$ multiply by the percentage which is 4.5% = 0.045
40,000 x 0.045=1,800$

8 0

3 years ago

Read 2 more answers

Simplify, state all restrictions.

Kipish [7]

The simplified expression is $\frac{1 - x - y}{x + y}$ and the restriction is $y \ne -x$

<h3>How to simplify the expression?</h3>

The expression is given as:

$\frac{x - y}{4x^2 - 8xy + 3y^2} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{x^2 - y^2} -1$

Express x^2 - y^2 as (x + y)(x - y) and factorize other expressions

$\frac{x - y}{(2x - y)(2x - 3y)} \div \frac{2x + y}{2x - 3y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1$

Rewrite the expression as products

$\frac{x - y}{(2x - y)(2x - 3y)} \times \frac{2x - 3y}{2x + y} \times \frac{4x^2 - y^2}{(x - y)(x + y)} -1$

Cancel out the common factors

$\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{4x^2 - y^2}{(x + y)} -1$

Express 4x^2 - y^2 as (2x - y)(2x + y)

$\frac{1}{(2x - y)} \times \frac{1}{2x + y} \times \frac{(2x - y)(2x + y)}{(x + y)} -1$

Cancel out the common factors

$\frac{1}{x + y} -1$

Take the LCM

$\frac{1 - x - y}{x + y}$

Hence, the simplified expression is $\frac{1 - x - y}{x + y}$ and the restriction is $y \ne -x$