Question

If an arrow is shot upward on the moon with a velocity of 50 m/s, its height (in meters) after t seconds is given by H = 50t − 0.83t^2.

Answer 1

Answer:

The velocity is: 48.34m/s

Step-by-step explanation:

Given

$u = 50m/s$ --- initial velocity

$h = 50t - 0.83t^2$

Required

The velocity after 1 second

We have:

$h = 50t - 0.83t^2$ and $t = 1$

Differentiate

$h' = 50 - 1.66t$

We have that:

$v = h'$

So, the equation becomes

$v = 50 - 1.66t$

Substitute 1 for t

$v = 50 - 1.66*1$

$v = 50 - 1.66$

$v = 48.34$