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mixas84 [53]
2 years ago
5

Construct an equilateral triangle of side 7cm and construct circumcircle.

Mathematics
1 answer:
zalisa [80]2 years ago
6 0

Answer:

To do this, all you need is to draw triangle with each side being 7 cm, and a circle that intersects all three of its corners.

Step-by-step explanation:

  1. With a ruler and a pencil, draw a 7cm line.
  2. With a compass set to a radius of 7cm draw an arc centered around the right end of the line.
  3. With the same compass, still at 7cm, draw an arc centered around the left end of the line.
  4. These two arcs will intersect on either side of the line (you only need one side, so you only need a small arc in the right place, roughly where you think the third point if the triangle is.
  5. Where those arcs intersect is the third point on your triangle.  Mark that, and then trace two lines from that point to either end of the line segment you started with.

<em>You now have an equilateral triangle with 7cm sides.  Next you need to draw the circle</em>

  1. Measure the halfway point on two of your three lines.
  2. Draw a line from that each of those halfway points to the opposite corner. The new lines you're drawing will be perpendicular to the edge your measuring against.
  3. You have now drawn two line segments, and they intersect in the center of the circle.  Now take your compass and set its radius to the distance from that center point to one of the three corner points.
  4. Centered on that middle point, trace a circle with the selected radius.

And you're done!

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dezoksy [38]

Answer:

The division was computed incorrectly.

Step-by-step explanation:

Given

Workings:

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\frac{8}{5} = 1.6 = 160\%

Required

Explain his error

The question says 5/8

Instead, Alejandro's working shows 8/5.

This working is done in an incorrect order and the correct solution is:

Let

x = \frac{5}{8}

Solve the fraction

x = 0.625

Multiply by 100%

x = 0.625 * 100\%

x = 62.5\%

<em>Hence, option (a) is correct.</em>

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Triangle ABC contains the point A(5,2). Find the coordinates of A' after a reflection over the x-axis
Sholpan [36]

Answer:

Step-by-step explanation:

Should be 5,-2 OR NOT

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Mike hiked to a lake in 5.5 hours at an average rate of 2 1/5 miles per hour. Pedro hiked the same distance at a rate of 2 3/5 m
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Answer:

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Step-by-step explanation:

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3 years ago
What eigen value for this matix <br> (1 -2)<br> (-2 0)
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You find the eigenvalues of a matrix A by following these steps:

  1. Compute the matrix A' = A-\lambda I, where I is the identity matrix (1s on the diagonal, 0s elsewhere)
  2. Compute the determinant of A'
  3. Set the determinant of A' equal to zero and solve for lambda.

So, in this case, we have

A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]

The determinant of this matrix is

\left|\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right| = -\lambda(1-\lambda)-(-2)(-2) = \lambda^2-\lambda-4

Finally, we have

\lambda^2-\lambda-4=0 \iff \lambda = \dfrac{1\pm\sqrt{17}}{2}

So, the two eigenvalues are

\lambda_1 = \dfrac{1+\sqrt{17}}{2},\quad \lambda_2 = \dfrac{1-\sqrt{17}}{2}

5 0
3 years ago
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Please help need asap
frozen [14]

Answer:

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Step-by-step explanation:

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