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lord [1]
2 years ago
7

Help me!!!!!!!!!!!!!!!!!!!!!!!

Physics
1 answer:
Gemiola [76]2 years ago
8 0

Answer:a computer , machine forcery,0,push

Explanation:

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An air conditioner operating at steady state maintains a dwelling at 70oF on a day when the outside temperature is 90oF. If the
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30000 btuh /3413 btuh/kw. = 8.8 kw

8.8 kw/.746 kw/hp = 11.8 hp if COP is 1

11.8/3 hp (COP coefficient of performance) = 3.99 COP

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3.2 to 4.5 is expected COP range for an air cooled heat pump or a/c unit.
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3 years ago
Hydrogen fluoride gas (HF) and sodium hydroxide (NaOH) react in a test tube. They form water and sodium fluoride (NaF). Which ty
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The type of reaction that occurred in the test tube is ACID BASE REACTION.
Acid base reaction is a type of chemical reaction in which an acid and a base react together to form salt and water molecules. It is also known as neutralization reaction. For the question given above, the applicable chemical reaction is as follows:
HF + NaOH = NaF + H2O
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8 0
3 years ago
Please help me with my quiz
Oduvanchick [21]

Answer:

matter: A

data: E

variable: C

Controlled: D

Physical: B

Explanation:

8 0
2 years ago
Susan plans to grow cabbages and broccoli in her vegetable garden. Cabbages and broccoli grow best in clay soil. Which of these
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The correct option is B.
As we are told in the question, the cabbage and broccoli grow best in clay soil. From the options we are given, it can be seen that it is only option B that has the highest amount of clay soil. The soil that will be used should be one that has the highest content of clay.
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3 years ago
Two blocks, A and B, are connected by a rope. A second rope is connected to block B and a steady, horizontal tension force of T
Oksanka [162]

Answer:

40 N

Explanation:

We are given that

Speed of system is constant

Therefore, acceleration=a=0

Tension applied on block B=T=50 N

Friction force=f=10 N

We have to find the friction force acting on block A.

Let T' be the tension in string connecting block A and block B and friction force on block A be f'.

For Block B

T-f-T'=m_Ba

Where m_B=Mass of block B

Substitute the values

50-10-T'=m_B\times 0=0

T'==40 N

For block A

T'-f'=m_Aa

Where m_A=Mass of block A

Substitute the values

40-f'=m_A\times 0=0

f'=40 N

Hence, the friction force acting on block A=40 N

3 0
3 years ago
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