Answer:
Explanation:
mass of balloon (m) = 12.5 g = 0.0125 kg
density of helium = 0.181 kg/m^{3}
radius of the baloon (r) = 0.498 m
density of air = 1.29 kg/m^{3}
acceleration due to gravity (g) = 1.29 m/s^{2}
find the tension in the line
the tension in the line is the sum of all forces acting on the line
Tension =buoyant force + force by helium + force of weight of rubber
force = mass x acceleration
from density = \frac{mass}{volume} , mass = density x volume
- buoyant force = density x volume x acceleration
where density is the density of air for the buoyant force
buoyant force = 1.29 x (\frac{4]{3} x π x 0.498^{3}) x 9.8 = 6.54 N
- force by helium = density x volume x acceleration
force by helium = 0.181 x (\frac{4]{3} x π x 0.498^{3}) x 9.8 = 0.917 N
- force of its weight = mass of rubber x acceleration
force of its weight = 0.0125 x 9.8 = 0.1225 N
- Tension = buoyant force + force by helium + force of weight of rubber
the force of weight of rubber and of helium act downwards, so they
carry a negative sign.
- Tension = 6.54 - 0.917 - 0.1225 = 5.5 N
