Answer:
Step-by-step explanation:
Joint variation has the equation
y = kxz
k is the constant of variation and needs to be solved for using the initial conditions, then filled in later to another equation related to the given info to solve for something else. We are given y = amount of oil used, x = distance traveled, z-squared is the speed. Our equation looks like this, to be exact:
Filling in with the initial conditions:
which gives us the
k = .0014166667
Now we need to find the amount of oil used, y, under other circumstances, but this time we have our k.
which gives us that the amount of oil used, when rounded to the tenths,
y = 24.0 barrels
Answer:
3 ÷ 0.5
Step-by-step explanation:
Since each large square is 1 whole, and theirs five out of 10 columns that are distinctivly a different orange, it'd be 3 divided by 0.5.
let's notice, this is a Cube, namely all equal sides, and mind you it has 6 sides, Check the picture below.
There 7 blocks of hundreds which means each such block is equivalent to 100.
There are 5 blocks of tens, which means each such block is equivalent to 10.
There are 8 blocks of ones, which means each such block is equivalent to 1.
The total of these blocks will be = 7(100) + 5(10) + 8(10) = 758
We can make several two 3-digit numbers from these blocks. An example is listed below:
Example:
Using 3 hundred block, 2 tens blocks and 4 ones block to make one number and remaining blocks to make the other number. The remaining blocks will be 4 hundred blocks, 3 tens blocks and 4 ones blocks
The two numbers we will make in this case are:
1st number = 3(100) + 2(10) + 4(1) = 324
2nd number = 4(100) + 3(10) + 4(1) = 434
The sum of these two numbers is = 324 + 434 = 758
i.e. equal to the original sum of all blocks.
This way changing the number of blocks in each place value, different 3 digit numbers can be generated.
No if it was, the football would keep going up forever and keep going up faster as it was released
physics and common sense tells us that there is air resistance to slow the rise of the football
not exponential
