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3 years ago

What do you notice about the way energy is transferred between objects with different masses?

Physics

1 answer:

Galina-37 [17]3 years ago

7 0

I notice that the energy how it’s transferred it goes down slowly and the heat waves slowly rise up when conducting air

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80 POINT!!!!! IT'S WORTH IT!!!!!

alexandr402 [8]

because blah blah blah blah

3 0

3 years ago

What is the angle θ between vectors A⃗ and B⃗ if A⃗ =4ı^−4ȷ^ and B⃗ =−5ı^+7ȷ^?

ololo11 [35]

The characteristics of the scalar product allows to find the angle between the two vectors is:

The angle θ = 170º

The scalar product is the product between two vectors whose result is a scalar.

A . B = |A| |B| cos θ

Where A and B are the vectors, |A| and |B| are the modules of the vectors and θ at the angle between them.

The vector is given in Cartesian coordinates and the unit vectors in these coordinates are perpendicular.

i.i = j.j = 1

i.j = 0

A . B = (4 i - 4j). * -5 i + 7j)

A . B = - 4 5 - 4 7

A. B = -48

We look for the modulus of each vector.

|A| = $\sqrt{x^2 +y^2 }$

|A| = $\sqrt{4^2 + 4^2}$

|A| = 4 √2

|B| = $\sqrt{5^2 +7^2}$

|B| = 8.60

We substitute.

-48 = 4√2 8.60 cos θ

-48 = 48.66 cos θ

θ = cos⁻¹ $\frac{-48}{48.664}$

θ = 170º

In conclusion using the dot product we can find the angle between the two vectors is:

the angle θ = 170º

Learn more about the scalar product here: brainly.com/question/1550649

8 0

3 years ago

Help Me please!!!!!!!!!!!!!!!!!!!!! This My question on this test! I need This one! PLEASE!!!!!!!!

faltersainse [42]

Answer:

That is gold

Explanation:

3 0

3 years ago

Read 2 more answers

A ball attached to a string is whirled around in a horizontal circle having a radius R. If the radius of the circle is changed t

ivanzaharov [21]

Answer:

twice the original speed

Explanation:

the centripetal force is the force of an object moving in a circle of turning and it is given by the expression

$F=\frac{mv^{2} }{r}$

where f = force of the object

m = mass

v = velocity

r = radius of the circle

first we need to know what the orignal speed will be then we can tell what will happen if the radius of the circle is changed to 4R.

from the expression for the centripetal force, we need to make the velocity subject of the formula

$F = \frac{mv^{2} }{r} \\cross multiplying\\Fr =mv^{2} \\dividing both sides by m\\\frac{Fr}{m}=v^{2} \\taking the square root of both sides\\v=\sqrt{\frac{Fr}{m} }$

now, if the radius is changed to 4R

in the expression for v above i will need to just insert 4R in place of r

$v=\sqrt{\frac{4rF}{m} } \\$

the square root of 4 is 2,

therefore

$v=2\sqrt{\frac{rF}{m} }$

we can see that this is just twice of what the original speed was.

8 0

4 years ago

A car is being tested for safety by colliding it with a brick wall.The 1300 kg car is initially driving towards the wall at a sp

serg [7]

Answer:

44200 N

Explanation:

To calculate the average force exerted on the car, we will use the following equation

$\begin{gathered} Ft=\Delta p \\ Ft=m(v_f-v_i) \end{gathered}$

Where F is the average force, t is the time, m is the mass, vf is the final velocity and vi is the initial velocity of the car.

Replacing t = 0.5s, m = 1300 kg, vf = -2 m/s, and vi = 15 m/s and solving for F, we get

$\begin{gathered} F(0.5s)=(1300\text{ kg\rparen\lparen-2 m/s - 15 m/s\rparen} \\ F(0.5s)=(1300\text{ kg\rparen\lparen-17 m/s\rparen} \\ F(0.5s)=-22100\text{ kg m/s} \\ F=\frac{-22100\text{ kg m/s}}{0.5\text{ s}} \\ F=-44200\text{ N} \end{gathered}$

Therefore, the average force exerted on the car by the wall was 44200 N

4 0

1 year ago