Answer:
(a) The spring constant is 426N/m
(b) The mass is 5.65kg
Explanation:
(a) Energy stored in the spring (E) = 3.6J, extension (e) = 0.13m
E = 1/2Ke^2
3.6 = 1/2 × K × 0.13^2
K (spring constant) = 3.6×2/0.0169 = 426N/m
(b) F = Ke = 426 × 0.13 = 55.38N
Assuming the maximum acceleration (a) is 9.8m/s^2
Mass (m) = F/a = 55.38/9.8 = 5.65kg
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The mass of the man would remain the same…
His weight would change. Assuming the man’s weight on earth is 60N.
Since weight is a force, according to Newton’s second law, F = ma ( m = mass, a = acceleration due to gravity) First lets find the mass of the man, as it is required to find his weight on the moon.
F=ma[taking a of earth as10m/s
2
]
60=m.10[divide10onbothsides]
m=
10
60
= 6 Kg
Acceleration due to gravity on the moon is83%less than the acceleration due to gravity on earth(1.622m/s
2
).
F=ma
F=6.1.622=9.732 N
So a person weighting 60N on earth would approximately weight around 10Non the moon.
