The correct answer is a:Seawater
Answer:
(a) I=0.01 kg.m²
(b) I=0.03 kg.m²
Explanation:
Given data
Mass of disk M=2.0 kg
Diameter of disk d=20 cm=0.20 m
To Find
(a) Moment of inertia through the center of disk
(b) Moment of inertia through the edge of disk
Solution
For (a) Moment of inertia through the center of disk
Using the equation of moment of Inertia

For (b) Moment of inertia through the edge of disk
We can apply parallel axis theorem for calculating moment of inertia
Answer:
n = 1/5 and m = 3/5
Explanation:
The given quantity is :

Where
The dimension of [A] = [LT]
The dimension of [B] = [L²T⁻¹]
The dimension of [C] = [LT²]
We need to find the dimensions of n and m values.
Using dimensional analysis,
![[LT]=[L^2T^{-1}]^n[LT^2]^m\\\\\ [LT]=L^{2n}T^{-n}\times L^mT^{2m}\\\\\ [LT]=L^{2n+m}T^{2m-n}](https://tex.z-dn.net/?f=%5BLT%5D%3D%5BL%5E2T%5E%7B-1%7D%5D%5En%5BLT%5E2%5D%5Em%5C%5C%5C%5C%5C%20%5BLT%5D%3DL%5E%7B2n%7DT%5E%7B-n%7D%5Ctimes%20L%5EmT%5E%7B2m%7D%5C%5C%5C%5C%5C%20%5BLT%5D%3DL%5E%7B2n%2Bm%7DT%5E%7B2m-n%7D)
Comparing both sides,
2n+m=1 ....(1)
-n+2m=1 ,.....(2)
Solving (1) and (2), we get :
n = 1/5 and m = 3/5
Hence, this is the required solution.