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7nadin3 [17]
3 years ago
5

Hugger Polls contends that an agent conducts a mean of 53 in-depth home surveys every week. A streamlined survey form has been i

ntroduced, and Hugger wants to evaluate its effectiveness. The number of in-depth surveys conducted during a week by a random sample of 15 agents are: 53 57 50 55 58 54 60 52 59 62 60 60 51 59 56 Picture Click here for the Excel Data File At the .05 level of significance, can we conclude that the mean number of interviews conducted by the agents is more than 53 per week? (Round your answer to 3 decimal places.) Reject H0 : μ ≤ 53 when the test statistic is . Compute the value of the test statistic. (Round your answer to 3 decimal places.) Value of the test statistic What is your decision regarding H0? Reject Do not reject Estimate the p-value. The p-value is .
Mathematics
1 answer:
bonufazy [111]3 years ago
8 0

Answer: 4

Step-by-step explanation: yep

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A nature center offers 2 guided walks. The morning walk is two-third mile. The evening walk is three-sixths mile. Which walk is
MArishka [77]

Answer:

Evening walk is shorter.  

Step-by-step explanation:

We have been given that a nature center offers 2 guided walks. The morning walk is two-third mile. The evening walk is three-sixths mile. We are asked to find the shorter walk.

Let us compare both fractions by making the same denominator.

\text{Two-thirds}=\frac{2}{3}

\text{Two-thirds}=\frac{2\times2}{3\times2}

\text{Two-thirds}=\frac{4}{6}

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We will draw two rectangles, one with 6 sub-parts and other with three sub-parts.

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