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MissTica
3 years ago
5

HELP ME HELP ME PLEASE

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
3 0
What is that supposed to mean
MatroZZZ [7]3 years ago
3 0
I remember doing this sophomore year and the answer for the bottom one is the SAS congruence postulate and the answer for the top one is also a congruent postulate I’m just not sure which one.
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zmey [24]
3,-4 is the correct anwser
3 0
3 years ago
What is 1.25 as a percent???
katrin [286]

The answer  for your questions is 125%

5 0
3 years ago
Read 2 more answers
Sin tita= 0.6892.find the value Of tita correct to two decimal places<br><br>​
Anvisha [2.4K]

Answer:

\theta \approx 6.28n + 2.38,  \quad  n \in \mathbb{Z}

or

\theta \approx 6.28n + 0.76, \quad n \in \mathbb{Z}

Considering \theta \in (0, 2\pi]

\theta \approx 2.38

or

\theta \approx 0.76

Step-by-step explanation:

\sin(\theta)=0.6892

We have:

\sin (x)=a \Longrightarrow x=\arcsin (a)+2\pi n \text{ or } x=\pi -\arcsin (a)+2\pi n \text{ as } n\in \mathbb{Z}

Therefore,

\theta= \arcsin (0.6892)+2\pi n, \quad n \in \mathbb{Z}

or

\theta = \pi -\arcsin (0.6892)+2\pi n, \quad  n\in \mathbb{Z}

---------------------------------

\theta \approx 6.28n + 2.38,  \quad  n \in \mathbb{Z}

or

\theta \approx 6.28n + 0.76, \quad n \in \mathbb{Z}

4 0
3 years ago
Arectangularplotoflandistobefencedinusingtwokinds of fencing. Two opposite sides will use heavy-duty fencing selling for $3 a fo
svlad2 [7]

Answer:

Dimensions of the rectangular plot will be 500 ft by 750 ft.

Step-by-step explanation:

Let the length of the rectangular plot = x ft.

and the width of the plot = y ft.

Cost to fence the length at the cost $3.00 per feet = 3x

Cost to fence the width of the cost $2.00 per feet = 2y

Total cost to fence all sides of rectangular plot = 2(3x + 2y)

2(3x + 2y) = 6,000

3x + 2y = 3,000 ----------(1)

3x + 2y = 3000

      2y = 3000 - 3x

      y = \frac{1}{2}[3000-3x]

      y = 1500 - \frac{3x}{2}

Now area of the rectangle A = xy square feet

A = x[1500-\frac{3x}{2}]

For maximum area \frac{dA}{dx}=0

A' = \frac{d}{dx}(1500x-\frac{3}{2}x^{2}) = 0

1500 - 3x = 0

3x = 1500

x = 500 ft

From equation (1),

y = 1500 - \frac{3}{2}\times 500

y = 1500 - 750

y = 750 ft

Therefore, for the maximum area of the rectangular plot will be 500 ft × 750 ft.

two fencing 3(500+500) = $3000

other two fencing 2(750+750) = $3000

8 0
3 years ago
Can someone help me with this? (screenshot of problem attached)
mote1985 [20]

Answer:

Step-by-step explanation:

Hello. Would love to try and help, your screenshot is not showing up when I click on it though.

7 0
4 years ago
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