What do you call a character’s direct speech in a literary text?

A national car rental company recently conducted a study in which cars with automatic and standard transmissions (factor A – Sam

Rom4ik [11]

Answer:

A national car rental company recently conducted a study recently in which cars with automatic and standard transmissions (factor B) were rented to male and female customers (factor A). Three customers in each category were randomly selected and the miles driven per day was recorded as follows:

Based on the design of this study, how many degrees of freedom will be associated with the mean square for factor A?

8312

6 0

3 years ago

Jane has six different hamsters for which she has two cages, one red and one blue. She wants to put three hamsters in the red ca

Luba_88 [7]

Answer:

12 ways

Step-by-step explanation:

The different ways to choose which three hamsters to put in the red cage.

At first , she must choose one of the two of the hamsters, Felix and Oscar, because they do not get along and cannot be in the same cage.

So, the number of ways to choose one of them = 2

Then she will choose 2 from the remaining 4 hamsters (order does not matter)

The number of ways to choose 2 from 4 = 4C2 = 6

So, the total number of ways = 2 * 6 = 12

4 0

3 years ago

If a plane is cruising at an altitude of 30,000

madam [21]

Answer:

244,330 feet

Step-by-step explanation:

Please refer to the image attached for explanations

7 0

3 years ago

What is cos(3pi)? 1 0 -1 -2

Dafna1 [17]

C: -1 is the answer

5 0

3 years ago

Read 2 more answers

A certain town never has two sunny days in a row. Each day is classified as being either sunny, cloudy (but dry), or rainy. If i

11111nata11111 [884]

Answer:

the proportion of days that are Sunny is 0.2

Step-by-step explanation:

Given the data in the question;

Using markov chain;

3 states; Sunny(1), Cloudy(2) and Rainy(3)

Now, based on given conditions, the transition matrix can be obtained in the following way;

$\left[\begin{array}{ccc}0&0.5&0.5\\0.25&0.5&0.25\\0.25&0.25&0.5\end{array}\right]$

so let the proportion of sunny, cloudy and rainy days be S, C and R respectively.

such that, from column 1

S = 0.25C + 0.25R -------------let this be equation 1

from column 2

0.5C = 0.5S + 0.25R

divided through by 0.5

C = S + 0.5R ---------------------- let this be equation 2

now putting equation 2 into equation;

S = 0.25(S + 0.5R) + 0.25R

S = 0.25S + 0.125R + 0.25R

S - 0.25S = 0.375R

0.75S = 0.375R

S = 0.375R / 0.75

S = 0.5R

Therefore,

from equation 2; C = S + 0.5R

input S = 0.5R

C = 0.5R + 0.5R

C = R

Now, we know that, the sum of the three proportion should be equal to one;

so

S + C + R = 1

since C = R and S = 0.5R

we substitute

0.5R + R + R = 1

2.5R = 1

R = 1/2.5

R = 0.4

Hence, the proportion of days that are Rainy is 0.4

C = R

C = 0.4

Hence, the proportion of days that are Cloudy is 0.4

S = 0.5R

S = 0.5(0.4)

S = 0.2

Hence, the proportion of days that are Sunny is 0.2

8 0

3 years ago