You have to derive for a multiplication in both terms:
=e^x+xe^x-(e^x-1 + (x-2)e^x-1) now apply distributive property in the last term:
=e^x+xe^x+e^x-1-xe^x-1 now replace each x by 0 (x=0)
=1 + 0 + e^-1 + 0 = 1+ e^-1 = 1.3679
(I)1.272727... = 14/11
(II)0.1282828...= 127/990
(The solution is in the picture
NB : the two points on the two numbers in the solution means those two numbers are recurring or repeating )
Answer:it’s b
Step-by-step explanation:
On edn
Answer:
the hell you are talking about?
Step-by-step explanation:
Answer:
u put the algebraic like terms together whether they add or subtract each other