Question

A DC motor connected to a switch-mode dc-dc converter goes into regenerative braking mode. The average current being supplied by the dc motor is 20 A. In the equivalent circuit of the dc motor, Ea=103 V, Ra=0.19 Ohms, and La=4 mH. Calculate the average power flow into the converter. Round answer to the nearest whole number.

Answer 1

Answer:

The correct answer is "2524 W".

Explanation:

The given values are:

Ia = 20 A

Ea = 103 V

Ra = 0.19 Ω

La = 4 mH

According to KVL,

⇒ $V_0=E_a-I_aR_a$

On substituting the given values in the above equation, we get

⇒      $=103-(20)(0.19)$

⇒      $=103-3.8$

⇒      $=126.2 \ V$

Now,$=126.2\times 20$

The average power flow into the converter will be:

⇒ $P=V_0 I_a$

On substituting the given values, we get

⇒     $=(126.2\times 20)$

⇒     $=2524 \ W$