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sweet [91]
3 years ago
7

Can reverse magnetic compulsion be turned in to a form of non-lethal weaponry?

Physics
1 answer:
murzikaleks [220]3 years ago
8 0

yes because the magnet would repulse the bullet or whatever weapon they have thus prevention harm

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Which of the balls will exert the smallest force on object A?Why
olganol [36]
The 1kg ball would exert the smallest force.

As force = mass x gravity, this means that the smaller the mass (kg), the lesser the force.

When the mass is lighter (1kg):

Force = mass x gravity
Force = 1 x 9.8
Force = 9.8N

Compared to when the mass is heavier (10kg)

Force = mass x gravity
Force = 10 x 9.8
Force = 98N

Where this proves that the lighter the mass, the smaller the force exerted.
6 0
2 years ago
I have a density of 1.61g/cm^3 and a mass of 28g. Find the missing value
Tamiku [17]

The missing value is the 'k' that should appear between '28' and 'g' .

Nobody has a mass of 28g.

My new grandson, who was born yesterday (January 29, 2019), had a mass of 4,039g at birth.  

Mother and son are happy and resting comfortably today, in Kfar Tapuach, Samaria, Israel.

8 0
3 years ago
The diameter of 0-gauge copper wire is 8.252 mm. Find the resistance of a 1.00-km length of such wire used for power transmissio
Dafna1 [17]

Answer:

The value is R = 0.321 \ \Omega

Explanation:

From the question we are told that

   The diameter is  d =  8.252 \  mm  =  0.008252 \  m

    The length of the wire is  l =  1.0 \  km  =  1000 \  m

   Generally the cross sectional area of the copper wire is mathematically represented as

           A  = \pi * \frac{d^2}{4}

=>        A  =  3.142  * \frac{ 0.008252^2}{4}

=>         A  =  5.349 *10^{ - 5} \  m^2

Generally the resistance is mathematically represented as

      R =  \frac{\rho  *  l }{A }

Here \rho is the resistivity of copper with the value  \rho =  1.72*10^{-8} \ \Omega \cdot m

=>    R =  \frac{1.72 *10^{-8}  *   1000 }{5.349 *10^{ - 5}  }

=>    R = 0.321 \ \Omega

5 0
2 years ago
When 587.9 nm passes through a single slit 0.73 mm wide, it creates a diffraction pattern. (a) What distance away is the wall if
storchak [24]

If the first minimum is 0.86 mm from the central maximum, the distance away is 1.07 meters.

Given the data in the question;

  • Wavelength; \lambda = 587.9nm = 5.879*10^{-7}m
  • Width of slit; a = 0.73mm = 0.00073m
  • First minimum; y = 0.86mm = 0.00086m
  • Since its first, order number; m = 1
  • Distance;  L = \ ?

From Thomas Young's single slit experiment:

\frac{a*y}{L} = m * \lambda    

Where a is the width of the slit, y is first minimum, L is the distance, m is the order number and λ is the wavelength.

We substitute our values into the equation

\frac{0.00073m\ *\ 0.00086m}{L}  = 1\ *\  ( 5.879*10^{-7}m)\\\\\frac{0.0000006278m^2}{L}  = 5.879*10^{-7}m\\\\L = \frac{0.0000006278m^2}{5.879*10^{-7}m} \\\\L = 1.07m

Therefore, if the first minimum is 0.86 mm from the central maximum, the distance away is 1.07 meters.

Learn more: brainly.com/question/16051099

4 0
2 years ago
Read 2 more answers
¿Qué velocidad inicial debe impartirse a una masa de 5kg para elevarla a una altura de 10m? ¿Cuál es la energía total en cualqui
Snowcat [4.5K]
Cada 100 cm es de 1 m por lo que tomar los kilos a su vez a cm, a continuación, a su vez a metros
6 0
3 years ago
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