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3 years ago

Can reverse magnetic compulsion be turned in to a form of non-lethal weaponry?

Physics

1 answer:

murzikaleks [220]3 years ago

8 0

yes because the magnet would repulse the bullet or whatever weapon they have thus prevention harm

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A circular loop carrying a current of 1.6 A is oriented in a magnetic field of 0.30 T. The loop has an area of 0.14 m 2 and is m

konstantin123 [22]

Answer:

The torque on the loop is $2.4 \times 10^{-2}$ Nm

Explanation:

Given:

Current $I = 1.6$ A

Magnetic field $B = 0.30$ T

Area of loop $A = 0.14$ $m^{2}$

Angle between magnetic field and area vector $\theta =$ 21°

Form the formula of torque in case of magnetic field,

г $= MB \sin \theta$

Where $M =$ magnetic moment

$M = IA$

г $= IAB \sin 21$

г $= 1.6 \times 0.30 \times 0.14 \times 0.3583$

г $=2.4 \times 10^{-2}$ Nm

Therefore, the torque on the loop is $2.4 \times 10^{-2}$ Nm

7 0

3 years ago

Suppose there are 100,000 atoms of a radioactive substance that has a ½ life of 10 minutes. How many atoms will remain after 40

dezoksy [38]

Answer:

c. 12,500

Explanation:

Original number of atoms = 100,000 atoms

Half- life = 10min

Unknown:

The number of atoms that will remain after 10min = ?

Solution:

The half - life is the time taken for half of a radioactive substance to decay by half.

Time taken Number of atom half life

10min 100000 _

20min 50000 1

30min 25000 2

40min 12500 3

6 0

3 years ago

A pendulum has a mass of 3kg and is lifted to a height of .3m. What is the maximum speed of the pendulum

Kryger [21]

Given data

*The given mass of the pendulum is m = 3 kg

*The given height is h = 0.3 m

The formula for the maximum speed of the pendulum is given as

$v_{\max }=\sqrt[]{2gh}$

*Here g is the acceleration due to the gravity

Substitute the values in the above expression as

$\begin{gathered} v_{\max }=\sqrt[]{2\times9.8\times0.3} \\ =2.42\text{ m/s} \end{gathered}$

Hence, the maximum speed of the pendulum is 2.42 m/s

7 0

1 year ago

Yall i need this asap

liq [111]

ASAP Ferg?
Edge 2020

6 0

2 years ago

A 2 kg blob of putty moving at 3 m/s slams into a 3 kg blob of putty at rest. Which blob has the most momentum prior to the coll

Ray Of Light [21]

initial momentum of 2 kg blob is given as

$P_1 = m_1v_1$

here we have

$m_1 = 2kg$

$v_1 = 3m/s$

$P_1 = 3(2) = 6 kg m/s$

initial momentum of 3 kg blob is given as

$P_2 = m_2v_2$

here we have

$m_2 = 3kg$

$v_2 = 0m/s$

$P_2 = 3(0) = 0 kg m/s$

So initially 2 kg Blob has most momentum before they collide

5 0

3 years ago