Which of the following titles best describes the air mass shown at arrow A?

If the coefficient of kinetic friction between tires and dry pavement is 0.93. What is the shortest distance in which you can st

Alexeev081 [22]

The shortest distance over which a car moving at 33.6 m/s may be stopped by locking the brakes is 61.93 m

The kinetic friction coefficient is 0.93.

using N, where N is the normal reaction = mg, frictional force can be evaluated.

Fr =- 0.93 x 9.8 = -9.114 m/s²

Friction, which takes the form of a decelerating force, helps the car come to a stop.

This frictional force equals the ma force,

where ma = 7.84 m and a = 7.84 m/s2.

However, this acceleration is negative at 7.84 m/s2 since it is decelerating.

So, using the equations of motion,

v² = u² + 2ax

where;

v = final velocity

u = initial velocity

a = acceleration

0 = 33.6² + 2(-9.114)x

0 = 1128.96 - 18.228x

18.228x = 1128.96

x = 1128.96/18.228

x = 61.93 m

Therefore, the shortest distance is 61.93 m

To know more about shortest distance refer to: brainly.com/question/16751593

#SPJ4

4 0

2 years ago

a bicyclist travels with an averahe velocity of 15km/h north, for 20 minutes .what is his displacement ?

Lunna [17]

Explanation:

velocity = 15 km/hr = 15×1000m / 60×60s

= 4.17 m/s

time= 20 min= 20 × 60s

= 1200s

displacement =?

we know that,

V = D / t

or, 4.17 = D / 1200

or, D = 4.17 × 1200

or,D = 5004 m

7 0

3 years ago

Which landscape will erode more quickly? Assume the same precipitation and average temperature in each landscape.

Artemon [7]

Answer:

B. Landscape B

Explanation:

Shale is fine sediment pressed together to form rock.

Sandstone is larger (sand-grain-sized) sediment cemented together to form rock.

Shale erodes faster, as evidenced by the second attachment. That attachment shows erosion of a rock face consisting of interbedded shale and sandstone. The shale has receded significantly, leaving the sandstone layers with space between them.

5 0

3 years ago

Physics Homework MathPhys homie if you see this pls help

cluponka [151]

Answer:

1. -8.20 m/s²

2. 73.4 m

3. 19.4 m

Explanation:

1. Apply Newton's second law to the car in the y direction.

∑F = ma

N − mg = 0

N = mg

Apply Newton's second law to the car in the x direction.

∑F = ma

-F = ma

-Nμ = ma

-mgμ = ma

a = -gμ

Given μ = 0.837:

a = -(9.8 m/s²) (0.837)

a = -8.20 m/s²

2. Given:

v₀ = 34.7 m/s

v = 0 m/s

a = -8.20 m/s²

Find: Δx

v² = v₀² + 2aΔx

(0 m/s)² = (34.7 m/s)² + 2 (-8.20 m/s²) Δx

Δx = 73.4 m

3. Since your braking distance is the same as the car in front of you, the minimum safe following distance is the distance you travel during your reaction time.

d = v₀t

d = (34.7 m/s) (0.56 s)

d = 19.4 m

6 0

4 years ago

A cannon ball is shot straight upward with a velocity of 72.50 m/s. How high is the cannon ball above the ground 3.30 seconds af

disa [49]

Answer:

Explanation:

Given

Cannon is fired with a velocity of $u=72.50\ m/s$