This is a very good visual representation. Whether it is the best, or not, depends on the purposes:
First, you can see right away where the top 25% (4th quartile) scored by looking at the right hand whisker.
Second, you get two measures of variation for the data, the range and the interquartile range. Finally, by looking at the left whisker, you can see that most of the variation comes from the bottom quartile: 3/4 of the students scored between 80 and 100, while 1/4 scored between 80 and 50.
As a teacher, I would want more detail about the bottom quartile. It might be that one student scored 50 and everyone else scored between 70 and 80. But I wouldn't need to have it graphically represented. This graph shows me that the class overall is in good shape: The median is close to 90. But there is at least one student, and up to 25 % of the class who did poorly on an exam that otherwise looks very easy.
Answer:
196 m^2
Step-by-step explanation:
Length of the side of the square = 14 m
area= 14×14 = 196 m^2
hope it helps...
have a great day!!
Answer:
Its d
Step-by-step explanation:
Compare the numbers to the graph
Answer:
Nate should leave a tip of $6.30.
Step-by-step explanation:
Since the total bill was $52.43, and Nate wants to leave a 12% tip, you would have to find out what 12% of 52.43 is. To find this out you would multiply 52.43 by 12%. This is 6.2916. So, to leave the waiter a 12% tip, Nate would leave about $6.30.
View the attached photo.
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The quadratic function, y = x2, has an x-intercept at the origin = TRUE</span>
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The quadratic function, y = x2 + 3, has an x-intercept at the origin = FALSE</span>
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From x = -2 to x = 0, the average rate of change for both functions is positive = FALSEWhen viewing a graph, you start from the left and go to right and from left to right from -2 to 0 the graph is declining.
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From x = -2 to x = 0, the average rate of change for both functions is negative = TRUEBoth are declining if you read the graph from left to right.
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For the quadratic function, y = x2, the coordinate (2, 3) is a solution to the equation of the function. = FALSE</span><span>
y = x^2
If we insert 2 into y = x^2 we get y = 4 but our point (2,3) has y = 3
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For the quadratic function, y = x2 + 3, the coordinate (2, 7) is a solution to the equation of the function. = TRUE
If we insert 2 for x, we see that y = x^2 + 3 = y = 2^2 + 3 = y = 7 and our y value in the point (2,7) is 7.