The second equation is <span>-5-2y=2, then
</span>
<span>-2y=2-(-5),
</span>
-2y=2+5,
-2y=7,
y=7÷(-2),
y=-3.5.
The first equation is 2x+5y=16, subtitude y=-3.5 in this equation, then
2x+5·(-3.5)=16,
2x-17.5=16,
2x=16-(-17.5),
2x=16+17.5,
2x=33.5,
x=33.5÷2,
x=16.75.
Answer: (16.75,-3.5)
Answer:
2/5
Step-by-step explanation:
Let's find the probability of each condition first.
For P(4), there is only one option: 4. This is 1 out of 5.
For P(even), this includes 4 and 6. However, we already had 4 from our last condition so we can remove this option. This is again 1 out of 5.
Adding them together, we will get 2/5.
The answer is 2/5
Answer:
P = 0.05
Step-by-step explanation:
12 months * 30 days each = 360 days
From 306 days, we have to select 8 days = 360C8 ways(Total ways)
We want each days from different month. First, we have to select 8 month from 12 month = 12C8 ways
---By selecting 8 month, we will select a days from each month. That can be done in = 30C1 * 30C1 * .................30C1 (8 ways) [From a month with 30 days, we can select a day in 30C1 ways = 30 ways]
Therefore P = Number of ways of selecting each days from different month / Total number of ways
P = 12C8 * 30^8 / 360C8
P = 495 * 656100000000 / 6469697679132645
P = 0.0501985588982791
P = 0.05
Hence the probability that each day is from a different month is 0.05
