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Helga [31]
3 years ago
13

In ARST, m R = 92° and mZS = 71°. Which list has the sides of ARST in order from

Mathematics
1 answer:
OLga [1]3 years ago
7 0

Answer:which grade are you

Step-by-step explanation:

If you are grade 7 to 9 I know

You might be interested in
I need the length of AC to the nearest 10th. If you can explain how you got it, that will be nice, but you don’t have too
Nezavi [6.7K]

Answer:

13.5

Step-by-step explanation:

\sin 64\degree = \frac{AC}{AB}\\\\AC = AB \sin 64\degree \\\\AC = 13.481910694\\\\AC \approx 13.5

4 0
3 years ago
Read 2 more answers
2x^3-x^2-3x=210<br> the answer is 5 but I want to know why.
mel-nik [20]

Answer:

x=5,\frac{-9+\sqrt{255}i }{4} ,\frac{-9-\sqrt{255}i }{4}

Step-by-step explanation:

1) Move all terms to one side.

2x^{3} -x^{2} -3x-210=0

2) Factor 2{x}^{3}-{x}^{2}-3x-210 using Polynomial Division.

1 -  Factor the following.

2x^{3} -x^{2} -3x-210

2 -  First, find all factors of the constant term 210.

1,2,3,4,5,6,7,10,14,15,21,30,35,42,70,105,210

3) Try each factor above using the Remainder Theorem.

Substitute 1 into x. Since the result is not 0, x-1 is not a factor..

2*1^{3} -1^{2} -3*1-210=-212

Substitute -1 into x. Since the result is not 0, x+1 is not a factor..

2(-1)^{3} -(-1)^{2} -3*-1-210=-210

Substitute 2 into x. Since the result is not 0, x-2 is not a factor..

2*2^{3} -2^{2} -3*2-210=-204

Substitute -2 into x. Since the result is not 0, x+2 is not a factor..

2{(-2)}^{3}-{(-2)}^{2}-3\times -2-210 = -224

Substitute 3 into x. Since the result is not 0, x-3 is not a factor..

2\times {3}^{3}-{3}^{2}-3\times 3-210 = -174

Substitute -3 into x. Since the result is not 0, x+3 is not a factor..

2{(-3)}^{3}-{(-3)}^{2}-3\times -3-210 = -264

Substitute 5 into x. Since the result is 0, x-5 is a factor..

2\times {5}^{3}-{5}^{2}-3\times 5-210 =0

------------------------------------------------------------------------------------------

⇒ x-5

4)  Polynomial Division: Divide 2{x}^{3}-{x}^{2}-3x-210  by x-5.

                                               2x^{2}                       9x                      42

                                      -------------------------------------------------------------------------

x-5                               |    2x^{3}                          -x^{2}                     -3x     -210

                                           2x^{3}                             -10x^{2}

                                        -----------------------------------------------------------------------

                                                                             9x^{2}                -3x       -210

                                     --------------------------------------------------------------------------

                                                                          42x                              -210

                                                                         42x                               -210

                                      -------------------------------------------------------------------------

5)  Rewrite the expression using the above.

2x^2+9x+42

(2x^2+9x+42)(x-5)=0

3) Solve for x.

x=5

4)  Use the Quadratic Formula.

1 - In general, given a{x}^{2}+bx+c=0 , there exists two solutions where:

x=\frac{-b+\sqrt{b^{2} -4ac} }{2a} ,\frac{-b-\sqrt{b^2-4ac} }{2a}

2 -  In this case, a=2,b=9 and c = 42.

x=\frac{-9+\sqrt{9^2*-4*2*42} }{2*2} ,\frac{-9-\sqrt{9^2-4*2*42} }{2*2}

3 - Simplify.

x=\frac{-9+\sqrt{255}i }{4} ,\frac{-9-\sqrt{255}i }{4}

5) Collect all solutions from the previous steps.

x=5,\frac{-9+\sqrt{255}i }{4} ,\frac{-9-\sqrt{255}i }{4}

4 0
2 years ago
Read 2 more answers
Can someone help me with this question?
arlik [135]

Try this solution:

1. m∠A=m∠L; m∠B=m∠M and m∠C=m∠N;

2. m∠B=m∠M=35° and m∠C=m∠N=95°;

3. m∠A=m∠L=180°-(m∠B+m∠C)=180-35-95=50°

answer: 50°

5 0
3 years ago
How to write 5x - 7y = 14 in function form
Slav-nsk [51]
5x-7y=14
-5x -5x
^
Subtract 5x from both sides

-7y=-5x+14
Divide by -7 by all of the numbers

y=-5/7x-2
7 0
3 years ago
In stats would a test looking at gender &amp; holiday preference would I do a Chi-squared test? Which is the explanatory &amp; w
Liula [17]

In statistics, a Chi-squared test may be used to determine holiday choice and gender and α (alpha) is the response variable.

<h3>What is the Chi-squared test? </h3>

A statistical technique called the chi-square test is used to compare actual outcomes with predictions.

The goal of this test is to establish if a discrepancy between actual and predicted data is the result of chance or a correlation between the variables you are researching.

Whether there is a statistically significant association between categorical variables is determined by the Chi-square test of independence.

This issue is addressed by a hypothesis test. The chi-square test of association is another name for this assessment.

Hence,in stats would a test looking at gender & holiday preference yes you can do  a Chi-squared test and α(alpha) is the response variable.

To learn more about the Chi-squared test refer;

brainly.com/question/14082240

#SPJ1

3 0
1 year ago
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