The given function is,

The graph can be drawn as,
The period will be distance between two consequetive maximas,

Thus, period is correct.
The amplitude can be determined as,

Thus, amplitue is incorrect.
The range is,

Thus, the range is correct.
The midline is,

Thus, the midline is correct.
Thus, option (b) is the solution.
The first one YES and the last one NO!
Answer:
Yes he has enough boxes to meet quota.
Step-by-step explanation:
4 x 8 = 32 This is over what he is requried to meet quota he is at quota.
Answer:
Its answer is -4..............