This is your answer say me if I am wrong
In ΔIJK, I K ‾ IK is extended through point K to point L, m ∠ J K L = ( 5 x − 3 ) ∘ m∠JKL=(5x−3) ∘ , m ∠ K I J = ( 2 x + 8 ) ∘ m
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1/2 would work for the blank space
because as shown in the image you could relate it to a whole for each one and put it to 100 to figure out what the blank could be
the 0.20 can be converted to 1/5 so that way you can put everything into the 100 group
because as shown in the image you could relate it to a whole for each one and put it to 100 to figure out what the blank could be
the 0.20 can be converted to 1/5 so that way you can put everything into the 100 group