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Firlakuza [10]
3 years ago
6

In ΔIJK, I K ‾ IK is extended through point K to point L, m ∠ J K L = ( 5 x − 3 ) ∘ m∠JKL=(5x−3) ∘ , m ∠ K I J = ( 2 x + 8 ) ∘ m

∠KIJ=(2x+8) ∘ , and m ∠ I J K = ( x − 1 ) ∘ m∠IJK=(x−1) ∘ . Find m ∠ J K L . M∠JKL.
Mathematics
1 answer:
fredd [130]3 years ago
3 0

Answer:

<em>22 degrees.</em>

Step-by-step explanation:

From the given question we are given the following:

Exterior angle m ∠ J K L = ( 5 x − 3 )°

Interior angles;

m∠KIJ=(2x+8)°

m∠IJK=(x−1)°

Note that the sum of interior angles is equal to the exterior angles;

Hence, m∠KIJ +m∠IJK = m∠JKL

Substitute the given values;

2x+8 + x -1 = 5x - 3

3x + 7 = 5x - 3

Collect like terms;

3x - 5x = -3-7

-2x = -10

x = 10/2

x = 5

Get m∠JKL

m∠JKL = 5x - 3

m∠JKL= 5(5)-3

m∠JKL = 25-3

m∠JKL = 22°

<em>hence the measure of m∠JKL is 22 degrees.</em>

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C will be your answer

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Reduce 1/2 × 16/9 is to lowest form​
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The correct answer will be "\frac{8}{9}".

Step-by-step explanation:

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3 years ago
Which is an equivalent form of the first equation that when added to second equation eliminates the x terms? 4/5 x-3/5y=18
Fittoniya [83]

Answer:

-8x + 6y = -180

Step-by-step explanation:

Given

\frac{4}{5} x-\frac{3}{5}y=18

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Required

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To do this, we simply make the coefficients of x to be opposite in both equations.

In the second equation, the coefficient of x is 8.

So, we need to make the coefficient of x -8, in the first equation.

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6 0
3 years ago
the length of a rectangle is 5 inches longer than twice the width and the area is 12 inches squared. Let l represent the length
svet-max [94.6K]

Answer:

Length = 8 inch , Width = \frac{3}{2} , This equation models the situation

Step-by-step explanation:

Given as ;

The Area of Rectangle is 12 inches²

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Let The Length = L inches

      The Width   = W inches

According to question ,

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∵ The Area of Rectangle = Length × width

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So ,  w = -4 , and w = \frac{3}{2}

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so ,  L = 5 + 3 = 8

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3 0
3 years ago
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