In ΔIJK, I K ‾ IK is extended through point K to point L, m ∠ J K L = ( 5 x − 3 ) ∘ m∠JKL=(5x−3) ∘ , m ∠ K I J = ( 2 x + 8 ) ∘ m
∠KIJ=(2x+8) ∘ , and m ∠ I J K = ( x − 1 ) ∘ m∠IJK=(x−1) ∘ . Find m ∠ J K L . M∠JKL.
1 answer:
Answer:
<em>22 degrees.</em>
Step-by-step explanation:
From the given question we are given the following:
Exterior angle m ∠ J K L = ( 5 x − 3 )°
Interior angles;
m∠KIJ=(2x+8)°
m∠IJK=(x−1)°
Note that the sum of interior angles is equal to the exterior angles;
Hence, m∠KIJ +m∠IJK = m∠JKL
Substitute the given values;
2x+8 + x -1 = 5x - 3
3x + 7 = 5x - 3
Collect like terms;
3x - 5x = -3-7
-2x = -10
x = 10/2
x = 5
Get m∠JKL
m∠JKL = 5x - 3
m∠JKL= 5(5)-3
m∠JKL = 25-3
m∠JKL = 22°
<em>hence the measure of m∠JKL is 22 degrees.</em>
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