Find the empirical formula of the following compounds:
1 answer:
The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.
<h3>What is empirical formula?</h3>The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.
<h3>How to find the empirical formula?</h3>Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.
Moles phosphorus = 0.903 g phosphorus = 0.0293 mol
Moles bromine 6.99 g bromine=0.0875 mol
The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3
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<u>Answer:</u> The concentration of hydrogen ion and bromoacetate ion is 0.0132 M and 0.0132 M resepectively and that of bromoacetic acid is 0.0868 M
<u>Explanation:</u>
We are given:
Molarity of bromoacetic acid = 0.100 M
Percent of ionization = 13.2 %
The chemical equation for the ionization of bromoacetic acid follows:
1 mole of bromoacetic acid produces 1 mole of bromoacetate ion and 1 mole of hydrogen ion
Molarity of hydrogen ion = 13.2 % of 0.100 =
Molarity of bromoacetate ion = molarity of hydrogen ion = 0.0132 M
Molarity of bromoacetic acid = Molarity of solution - Molarity of ionized substance
Molarity of bromoacetic acid = 0.100 - 0.0132 = 0.0868 M
Hence, the concentration of hydrogen ion and bromoacetate ion is 0.0132 M and 0.0132 M resepectively and that of bromoacetic acid is 0.0868 M