I would go with C because that seems like the best answer choice
I legitimately think it's 87.3 grams
Bonding MO's have lower energy than antibonding MO's. The bonding MO's lower energy, even lower than its constituent atomic orbitals, accounts for the stability of a molecule in relation to its individual atoms. However, the sum of energy of the MO's must equal the sum of energy of the AO's.
<h3>What is atomic orbital?</h3>
An atomic orbital is a function in atomic theory and quantum mechanics that describes the location and wave-like behavior of an electron in an atom. This formula can be used to calculate the likelihood of locating any atom's electron in any given location surrounding the nucleus. The phrase atomic orbital can also refer to the actual region or place where the electron is projected to be present given the orbital's mathematical form.
Each orbital in an atom is defined by a set of values of the three quantum numbers n, l, and ml, which correspond to the energy, angular momentum, and an angular momentum vector component of the electron, respectively (magnetic quantum number).
To learn more about atomic orbital visit:
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Answer:
0.090 J/(mmol·°C) × (1000 mmol/mole × 1 kJ/(1000 J)) = 0.090 kJ/mole
Explanation:
The unit of conversion from kilo-Joules to Joules is given as follows;
1000 Joules = 1 kilo-Joule
The unit of conversion from milimoles to moles is given as follows;
1000 milimoles = 1 Mole
Therefore, we have
The value of the given expression is 0.090 J/(mmol·°C) × 1000 mmol/mole × 1 kJ/(1000 J) = 0.090 kJ/mole
0.090 J/milimole = 0.09 kJ/mole.
Answer:
The C22- ion is stable
Explanation:
The C22- ion is a stable ion having a bond order of three. It has a favourable stabilization energy of 6∆ compared to 4∆ in C2. In the carbide ion carbon firms three bonds rather than two in dicarbon, hence the formation of the carbide ion is preferred. The molecular orbital configuration of the carbide ion is shown in the image attached.
