12 times breathe give 240 ml of pure
. Each breathe gives 20 ml of
.
Let us consider, volume of air per breathe= x ml.
Pure
from inhaled air=
ml and Pure
from exhaled air=
ml.
Pure
from inhaled and exhaled air= 20 ml
So,
+
= 20
Therefore, x = 55.5 ml
So, volume of air per breath= 55.5 ml.
The molar mass is 294.1527 g/mol
Answer: On losing 6 moles of water, cobalt chloride forms unstable violet-coloured ions, before generating its stable blue-coloured anhydrous form.
Explanation:
The hydrated cobalt chloride loses its 6 water of crystallization, then dissociates into ions: cobalt ions and chlorine ions that appear violet, and quickly combined to form the stable anhydrous Cobalt chloride with blue colour.
Answer:
the initial concentration of SCN- in the mixture is 0.00588 M
Explanation:
The computation of the initial concentration of the SCN^- in the mixture is as follows:
As we know that

As it is mentioned in the question that KSCN is present 10 mL of 0.05 M
So, the total milimoles of SCN^- is
= 10 × 0.05
= 0.5 m moles
The total volume in mixture is
= 45 + 10 + 30
= 85 mL
Now the initial concentration of the SCN^- is
= 0.5 ÷ 85
= 0.00588 M
hence, the initial concentration of SCN- in the mixture is 0.00588 M