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poizon [28]
3 years ago
13

Find the area of the shaded region in square units ​

Mathematics
1 answer:
Kaylis [27]3 years ago
5 0

Answer:

There is nothing there...

Step-by-step explanation:

I wish I could help you but you need to put in a picture or diagram

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HELP PLEASE ANSWER QUICKLY!
quester [9]

Answer:

3 twelths is your answer :)

8 0
3 years ago
Read 2 more answers
2(x + 3) = x - 4 <br>And <br>4(5x-2)=2(9x+3)<br>​
weqwewe [10]

2x+6 - х -4

2x - x = - 4 - 6

x=-10

20x - 8 = 18x +6

20x - 18x = 6 +8

2x = 14

x=7

4 0
3 years ago
4 students is ____% of 20 students
Rudiy27

Answer:

20%

Step-by-step explanation:

20 * 20% = 4

or you can change it to a decimal

20 * .2 = 4

hope this helped! :)

3 0
2 years ago
A different map has a scale of 1:50000
Deffense [45]

Answer:

8 Km

Step-by-step explanation:

16 x 50000 = 800,000 cm

800,000 cm = 8,000 m

8,000 m = 8 km

I hope this helps, if not sorry

6 0
3 years ago
Which is the equation of a hyperbola centered at the origin with x-intercept +\- 3 and asymptote y=2x
Radda [10]

Answer:

{\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}

Step-by-step explanation:

The hyperbola has x-intercepts, so it has a horizontal transverse axis.

The standard form of the equation of a hyperbola with a horizontal transverse axis is  \dfrac{(x - h)^{2}}{a^{2}} - \dfrac{(y - k)^{2}}{b^{2}} = 1

The center is at (h,k).

The distance between the vertices is 2a.

The equations of the asymptotes arey = k \pm \dfrac{b}{a}(x - h)

1. Calculate h and k. The hyperbola is symmetric about the origin, so  

h = 0 and k = 0

2. For 'a': 2a = x₂ - x₁ = 3 - (-3) = 3 + 3 = 6

a = 6/2 = 3  

3. For 'b': The equation for the asymptote with the positive slope is  

y = k + \dfrac{b}{a}(x - h) = \dfrac{b}{a}x

Thus,  asymptote has the slope of

\begin{array}{rcl}m& =& \dfrac{b}{a}\\\\2& =& \dfrac{b}{3}\\\\b& =& \mathbf{6}\end{array}

4.  The equation of the hyperbola is

\large \boxed{\mathbf{\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}}

The attachment below represents your hyperbola with x-intercepts at ±3 and asymptotes with slope ±2.

7 0
3 years ago
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