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2 years ago

If BCDE is congruent to OPQR, then DE¯¯¯¯¯¯ is congruent to ?

Mathematics

2 answers:

anygoal [31]2 years ago

5 0

The answer is QR HOPE THIS HELPS!!! XD

Sphinxa [80]2 years ago

5 0

Answer: Qr i took the test

bc go to op and de go to qr

congruent means same point on different shapes

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What is the shape of the cross section taken parallel to the base of a square pyramid

horsena [70]

Answer:

A square

Step-by-step explanation:

A parallel cross section will be the same shape of the base. Since it's a square base, all parallel cross sections will also be parallel. Think of it as a different floor of a pyramid shaped building.

4 0

3 years ago

Read 2 more answers

(x – 2)^2 + 20 = 0

seraphim [82]

Answer:

x = 2 ± 2 sqrt(5)i

Step-by-step explanation:

(x – 2)^2 + 20 = 0

Subtract 20 from each side

(x – 2)^2 + 20 -20=0 -20

(x – 2)^2 =- 20

Take the square root of each side

sqrt((x – 2)^2) =±sqrt(- 20)

x-2 = ±sqrt(- 20)

We know sqrt(ab) = sqrt(a) sqrt(b)

x-2 = ±sqrt(- 1) sqrt(20)

We know the sqrt (-1) = i

x-2 = ±i sqrt(4*5)

x-2 = ±i sqrt(4) sqrt(5)

Add 2 to each side

x-2+2 = 2 ±i sqrt(4) sqrt(5)

x = 2 ±i 2 sqrt(5)

x = 2 ± 2 sqrt(5)i

7 0

2 years ago

A circle is inscribed in an equilateral triangle. A point in the figure is selected at random. Find the probability that the poi

liubo4ka [24]

Answer:

The correct answer is first option 60%

Step-by-step explanation:

The radius of a circle is inscribed in an equilateral triangle with side a = a/2√3

To find the area of equilateral triangle

Here side be 'a'

Area of equilateral = √3a²/4

To find the area of circle

Here radius = a/2√3

Area = πr²

= π(a/2√3)

= 3.14a²/12

To find the probability

probability = area of circle/area of triangle

= 3.14a²/12/ √3a²/4

= 3.14/3√3

= 0.6043 ≈ 60.43 % 60 %

The correct answer is first option 60%

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2 years ago

Solve the right triangle (all sides and angles) please help!!!

andrew-mc [135]

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2 years ago

THE NUMBER 1-10 ARE IN A BAG, YOU TAKE 2 OUT WITHOUT REPLACEMENT. WHAT IS THE PROBABILITY OF DRAWING THE NUMBER 7 THE FIRST TIME

ehidna [41]

Answer:

1 / 18

Step-by-step explanation:

PROBABILITY OF DRAWING THE NUMBER 7 THE FIRST TIME = Number of favorable outcome / Total number of outcomes

Favorable outcome = 1

Total number of outcome (1,2,3,4,5,6,7,8,9,10) = 10

PROBABILITY OF DRAWING THE NUMBER 7 THE FIRST TIME = 1 / 10

PROBABILITY OF DRAWING AN EVEN NUMBER THE SECOND TIME = Number of favorable outcome / Total number of outcomes

Favorable outcome (2,4,6,8,10) = 5

Total number of outcomes (1,2,3,4,5,6,8,9,10) = 9

PROBABILITY OF DRAWING AN EVEN NUMBER THE SECOND TIME = 5/9

PROBABILITY OF DRAWING THE NUMBER 7 THE FIRST TIME AND THEN DRAWING AN EVEN NUMBER = 1 / 10 * 5 / 9 = 1 / 18

6 0

3 years ago