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topjm [15]
3 years ago
10

Hey, if anyone could be nice enough to do it, I need a Chegg account for only about a week after that I promise I won’t login. I

just need it for finals week, any help would be greatly appreciated!
Chemistry
1 answer:
valentinak56 [21]3 years ago
7 0
I don’t have a chegg account but i also have finals next week. we could work together !

have a great day mate and if you need the help ask me !
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The melting point of chromium is 1890. The melting point of argon is -189. Suggest a reason for this difference.
DanielleElmas [232]

Answer:

Different forces between atoms and difference in structure.

4 0
4 years ago
What is global warming
Bezzdna [24]

Answer:

a gradual increase in the overall temperature of the earth's atmosphere generally attributed to the greenhouse effect caused by increased levels of carbon dioxide, chlorofluorocarbons, and other pollutants.

Explanation:

8 0
3 years ago
A nitrogen oxide, containing 53.85% N, acts as a vasodilator, lowering blood pressure in the human body. What is its empirical f
jenyasd209 [6]

The empirical formula of the nitrogen oxide that acts as a vasodilator and lowers human blood pressure is N_4O_3. Empirical formula is the smallest whole number ratios of elements in a compound.  

FURTHER EXPLANATION

To get the empirical formula from mass percent data, the following steps are followed:

1. Get the mass percent data for all the elements that make up the compound.

2. Assume that there is 100 grams of sample compound. Determine the equivalent masses of each element using the mass percent given.

3. Convert the mass of each element to number of moles.

4. Divide each calculated mole by the smallest mole value.

5. The quotient will be the subscript of the element in the compound. If a decimal is obtained, round off the answers to the nearest whole number. Some exceptions to this are the following decimals: x.25, x.33, x.50, and x.75. When these decimals are obtained, all the subscripts are multiplied by a number that will result in a whole number.

Applying the steps to the problem,

STEP 1: Get the mass percent.

Mass % of N = 53.85

Mass % of O = (100 - 53.85) = 46.15

STEP 2: Assume that 100 g sample is used and convert the mass % to mass in grams.

mass of N = 53.85% x 100 g = 53.85 g

mass of O= 46.15% x 100 g = 46.15 g

STEP 3: Convert mass to moles by dividing the given mass by the formula mass.

moles \ of \ N \ = 53.85 \ g (\frac{1 \ mol}{14 \ g}) = 3.85 \\\\moles \ of \ O \ = 46.26 \ g \ (\frac{1 \ mol}{16 \ g}) \ = 2.89

The moles may be written as the temporary subscripts of the elements in the compound as follows:

N_{3.85}O_{2.89}

STEP 4: Divide the moles by the smallest mole value.

N_{3.85}O_{2.89}\\N_{ \frac{3.85}{2.89}} \ O _{ \frac{2.89}{2.89}} \\ N_{1.33}O_{1}\\

<u>STEP 5:</u> Multiply the subscripts by a number that would give the smallest whole number ratio.  

Since the decimal is 1.33 it cannot be rounded off to 1. It should be multiplied by 3 to get the smallest whole number.

NOTE: All subscripts must be multiplied by the same factor, 3.

N_{1.33}O_{1}\\3(N_{1.33}O_{1})\\\boxed {N_{4}O_{3}}

To check if the empirical formula is correct, calculate the mass % of each element based on the formula and compare with the given in the problem.

mass \ \%\ = (\frac{mass \ of \ element}{mass \ of \ compound}) x 100\\\\mass \ \% \ of \ N = \ \frac{(4)(14)}{(4)(14) \ + \ (3)(16)}

mass \ \% \ of \ N \ = 53.85%\\mass \ \% \ of \ O \ = (\frac{(3)(16)}{(4)(14)+(3)(16)}) \ 100\\mass \ \% \ of \ O \ = 46.15%

Since the values are the same from the given, the answer is correct.

LEARN MORE

  • Writing Chemical Formula brainly.com/question/4697698
  • Naming Compounds brainly.com/question/8968140
  • Mole Conversion brainly.com/question/12979299

Keywords: empirical formula, compounds

6 0
3 years ago
Read 2 more answers
I need help pleaseeee
solmaris [256]

Answer:

1 is H

3 is NA

the one below 14 is SI

16 is O

the one below 17 is Ci

the one below 18 is NE

Explanation:

hope this helps!

6 0
3 years ago
Read 2 more answers
Similar scientific themes are seen in what areas of science?
Nata [24]

Answer:

C-In all areas of science

Explanation:

Ap3x

6 0
3 years ago
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