Answer:
∠B ≅ ∠F ⇒ proved down
Step-by-step explanation:
<em>In the </em><em>two right triangles</em><em>, if the </em><em>hypotenuse and leg</em><em> of the </em><em>1st right Δ ≅</em><em> the </em><em>hypotenuse and leg</em><em> of the </em><em>2nd right Δ</em><em>, then the </em><em>two triangles are congruent</em>
Let us use this fact to solve the question
→ In Δs BCD and FED
∵ ∠C and ∠E are right angles
∴ Δs BCD and FED are right triangles ⇒ (1)
∵ D is the mid-point of CE
→ That means point D divides CE into 2 equal parts CD and ED
∴ CD = ED ⇒ (2) legs
∵ BD and DF are the opposite sides to the right angles
∴ BD and DF are the hypotenuses of the triangles
∵ BD ≅ FD ⇒ (3) hypotenuses
→ From (1), (2), (3), and the fact above
∴ Δ BCD ≅ ΔFED ⇒ by HL postulate of congruency
→ As a result of congruency
∴ BC ≅ FE
∴ ∠BDC ≅ ∠FDE
∴ ∠B ≅ ∠F ⇒ proved
40-15=g so they scored 25 this year and 25+15=40
12/x = 52/48
12 * 48 = 52x
x = 11.07 This is one way to do it.
Let the time = x
Let the part of the lawn = y
The general equation
y = k*x
52/100 = k * 12
k = 0.043333
y = 0.043333*x
y = 0.043333* 11.08
y = 0.48 which is what it should be.
Yet another way is to let y = kx
52 = k*12
k = 52/12
k = 4.33333333
y = 4.333333 * x
y = 4.333333 * 48
48 = 4.333333 * x
x = 11.07 which is just what you should expect.
Answer:
2800 - 4000
Step-by-step explanation:
40 × 70 = 2800
50 × 80 = 4000
