The genotype for a recessive trait found on the female chromosome is Xh. Xh are the recessive alleles of women. Recessive alleles only show their own effect if an individual has two copies of the same allele. Thus, a female with two Xh is a healthy female.
Answer:
Ss and ss
Explanation:
<em>Since the smooth trait (S) is dominant over the wrinkle trait (s), the genotype of the wrinkled pea parent is definitely </em><em>ss</em><em>.</em>
<em>Also, some of the progeny had wrinkled pea texture (ss). Each of the 2 wrinkled alleles must have been donated by each of the parent. It thus means that the smooth pea parent is heterozygous for the trait (</em><em>Ss</em><em>).</em>
Now, let us look at a cross between the two parents;
Ss x ss
Progeny: Ss, Ss, ss, ss.
Phenotypically, 50% of the progeny are smooth peas while 50% are wrinkled.
Looking at the population of each of the phenotype resulting from the cross. 252:247 is approximately a 50:50 ratio.
Hence, the genotypes of the two parents are Ss and ss.
The answer to your question is answer choice .1 Independent variable.
Answer:
where's your data? tho, i think we're answering the samee thingggg. here's mineee
