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alex41 [277]
3 years ago
10

1. The octane present in gasoline burns according to the following equation:

Chemistry
1 answer:
Harman [31]3 years ago
5 0

Answer:

n_{O_2}=343.75molO_2

Explanation:

Hello there!

In this case, according to the combustion of octane:

2C_8H_1_8+25O_2\rightarrow 16CO_2+18H_2O

We can see there is a 2:25 mole ratio of octane to oxygen; therefore, we can calculate the moles of oxygen via the following stoichiometric factor:

n_{O_2}=27.5molC_8H_1_8*\frac{25molO_2}{2molC_8H_1_8} \\\\n_{O_2}=343.75molO_2

Best regards!

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Technetium-104 has a half-life of 18.0 minutes. How much of a 165 g sample is left after 90.0 minutes?
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Answer:

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Explanation:

Given data:

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First of all we will calculate the number of half lives passes.

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At 2nd half life = 82.5 g/2  = 41.2 g

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