When you mix copper sulphate solution and steel wool, what is the chemical property that can be observed.

Chemistry

1 answer:

bazaltina [42]2 years ago

6 0

Answer:

Explanation:

depending on the activity series there will probably be a single replacement reaction possibly heat or color change and the copper precipitate out of solution

You might be interested in

How many molecules are in 100 g of C6H1206?

rjkz [21]

Answer: 100 grams of glucose represents 0.55 moles .

Explanation:

8 0

2 years ago

Write the word equation for the chemical reaction: Zn(s)+2HCl2(aq)--->ZnCl2(aq)+H2(g)

Vikki [24]

Zn(s) + 2HCl(aq) = ZnCl₂(aq) + H₂(g)

zinc + hydrochloric acid = zinc chloride + hydrogen

4 0

2 years ago

Be sure to answer all parts. Express the rate of reaction in terms of the change in concentration of each of the reactants and p

Tanzania [10]

Answer : The [H] is increasing at the rate of 0.36 mol/L.s

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$2D(g)+3E(g)+F(g)\rightarrow 2G(g)+H(g)$