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Alchen [17]
3 years ago
8

What is the predicted outcome for very low mass stars (those that are smaller than about the mass of the sun)?

Chemistry
1 answer:
White raven [17]3 years ago
4 0

Answer:

In case of low-mass stars,the outer layers of the low mass stars are expelled  as the core collapses such that the outer layers form a planetary nebula.

Explanation:

In case of low-mass stars,the outer layers of the low mass stars are expelled  as the core collapses such that the outer layers form a planetary nebula. The core remains as a white dwarf and finally become a black dwarf as it cools down. A low mass star consumes its core hydrogen and turns it into helium over its lifetime.

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A gas has a volume of 25.6 L at a temperature of 278 K. What will be the new temperature, in C, if
Inessa05 [86]
<h2>Hello!</h2>

The answer is: -97.37° C

<h2>Why?</h2>

According to the Charles and Gay-Lussac's Law we have that:

\frac{V}{T}=k

Where:

<em>v</em> is the volume of the gas

<em>t</em> is the temperature of the gas

<em>k </em>is the proportionality constant

From the Gay-Lussac's Law we also have the following relation:

\frac{V1}{T1}=\frac{V2}{T2}

Since we need to find the new temperature (T2) we can use the last equation:

\frac{V1}{T1}=\frac{V2}{T2}\\\\T2=\frac{V2*T1}{V1}=\frac{16.2L*278K}{25.6L}=175.92K

We are asked to find the temperature in Celsius degrees, so, we must convert the result (in K) to Celsius degrees:

Celsius=K-273.15=175.92-273.15=-97.37

So, the temperature is -97.37° C

Have a nice day!

7 0
3 years ago
Whats the answer? please help me​
dybincka [34]
Answer C
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Explanation
8 0
3 years ago
All atomic nuclei, except those of ordinary hydrogen, contain neutrons. <br> a. True<br> b. False
ozzi
This would be false
4 0
3 years ago
Read 2 more answers
What is the total number of valence electrons in the lewis structure of xeo4?
malfutka [58]
Here is a picture of which shows you how many valence electrons are in the Lewis structure of xeo4

6 0
3 years ago
Due to the small and highly electronegative nature of fluorine, the oxyacids of the this element are much less common and less s
steposvetlana [31]
We are told we have an oxyacid of the formula HOFO. We will assume the atoms are in this order and will draw a proper lewis structure for this compound by first drawing bonds between each of the 4 atoms and then place the remaining electron pairs on each atom:
      ..    ..    ..
H - O - F - O:
      ··   ··    ··
We can calculate the formal charge of an atom using the following formula:

Formal charge = [# of valence electrons] - [# of non-bonded electrons + # of bonds]

H: Formal charge = [1]-[0+1] = 0

O: Formal charge = [6]-[4+2] = 0

F: Formal charge = [7]-[4+2] = +1

O: Formal charge = [6]-[6+1] = -1

As we can see the overall charge of the molecule is neutral since the fluorine as a +1 charge and the oxygen a -1 charge.
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3 years ago
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