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e-lub [12.9K]
3 years ago
13

Calculate Ho298 for the process

Chemistry
1 answer:
Inga [223]3 years ago
4 0

Explanation:

As per the Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

Hence, according to this law the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

Sb + \frac{3}{2}Cl_2 \rightarrow SbCl_{3}    \Delta H^0_1 =  -314 kJ  ..........(1)

SbCl_{3} + Cl_2 \rightarrow SbCl_{5}    \Delta H^0_2 = -80kJ   ..............(2)

The final reaction is as follows:  

Sb + \frac{5}{2}Cl_{2} \rightarrow SbCl_{5}  \Delta H^0_3 = ?  .............(3)

Therefore, adding (1) and (2) we get the final equation (3) and value of \Delta H^{0}_{3} at 298 K will be as follows.

             \Delta H^{0}_{3} = \Delta H^{0}_{1} + \Delta H^{0}_{2}    

                       = -314 kJ + (-80) kJ

                       = -394 kJ

Thus, we can conclude that H^{o} at 298 K for the given process is -394 kJ.

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3 years ago
How many molecules are in 9.8 grams of calcium
solniwko [45]
Molar mass of Calcium ( Ca ) = 40.078 g/mol

Number of moles in 9.8 grams :

1 mole Ca -----------> 40.078 g
mole Ca -------------> 9.8 g

moles Ca = 9.8 / 40.078

moles Ca = 0.2445 moles

number of molecules:

1 mole ----------------> 6.02x10²³ molecules
0.2445 moles --------> ?

= 0.2445 * 6.02x10²³

= 1.47x10²³ molecules

hope this helps!.

7 0
3 years ago
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