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NeX [460]
3 years ago
14

PLS HELP ME TELL ME WHERE TO DRAW THE LINE

Mathematics
1 answer:
insens350 [35]3 years ago
5 0

Answer:

Step-by-step explanation:up your as

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dolphi86 [110]

720 \div 6 = 120
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Step-by-step explanation:

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Step-by-step explanation:

...

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Whats the GCF of 49 and 4
Irina18 [472]
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5 0
3 years ago
Brainliest first & correct!
Ilia_Sergeevich [38]

Answer:  Choice A

y = -3(x+2)^2 + 10

=================================================

Work Shown:

y = -3x^2-12x-2 is in the form y = ax^2+bx+c with

a = -3

b = -12

c = -2

The x coordinate of the vertex is

h = -b/(2a)

h = -(-12)/(2*(-3))

h = 12/(-6)

h = -2

We'll plug this into the original equation to find the corresponding y coordinate of the vertex.

y = -3x^2-12x-2

y = -3(-2)^2-12(-2)-2

y = 10

So k = 10 is the y coordinate of the vertex.

Overall, the vertex is (h,k) = (-2,10)

Meaning that we go from this general vertex form

y = a(x-h)^2 + k

to this

y = -3(x - (-2))^2 + 10

y = -3(x+2)^2 + 10

8 0
3 years ago
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