PLS HELP ME TELL ME WHERE TO DRAW THE LINE

Heather sees that two stores have similar sales. Store A says that 5 balloons will cost her $6.00 and store B says that 13 ballo

MatroZZZ [7]

Answer:

Store A and it would cost $32.40 (answer choice A)

Step-by-step explanation:

Let's start by studying how much she would pay for a single balloon on each store:

In store A: (5 balloons for $6) then per each balloon: $6/5 = $1.2 per balloon.

In store BA: (13 balloons for $16.25) then per each balloon: $16.25/13 = $1.25 per balloon.

This shows us that the better price is in store A if she wants to pay as little as possible. Now, at that price, if she wants to buy 27 balloons, she will be paying (27 times $1.2): 27 * $1.2 = $32.40

5 0

3 years ago

Verify identity: (sec(x)-csc(x))/(sec(x)+csc(x))=(tan(x)-1)/(tan(x)+1)

Nikitich [7]

So hmmm let's do the left-hand-side first

$\bf \cfrac{sec(x)-csc(x)}{sec(x)+csc(x)}\implies \cfrac{\frac{1}{cos(x)}-\frac{1}{sin(x)}}{\frac{1}{cos(x)}+\frac{1}{sin(x)}}\implies 
\cfrac{\frac{sin(x)-cos(x)}{cos(x)sin(x)}}{\frac{sin(x)+cos(x)}{cos(x)sin(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)sin(x)}\cdot \cfrac{cos(x)sin(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

now, let's do the right-hand-side then

$\bf \cfrac{tan(x)-1}{tan(x)+1}\implies \cfrac{\frac{sin(x)}{cos(x)}-1}{\frac{sin(x)}{cos(x)}+1}\implies \cfrac{\frac{sin(x)-cos(x)}{cos(x)}}{\frac{sin(x)+cos(x)}{cos(x)}}
\\\\\\
\cfrac{sin(x)-cos(x)}{cos(x)}\cdot \cfrac{cos(x)}{sin(x)+cos(x)}\implies \boxed{\cfrac{sin(x)-cos(x)}{sin(x)+cos(x)}}$

7 0

3 years ago

Lol not good with averages pls help

Ivenika [448]

15 is the answer i divided

6 0

3 years ago

Read 2 more answers

Tic is an isosceles triangle with a vertex angle I. if the angle of I is 70. find the measure of t.

Colt1911 [192]

Angles of a triangle = 180 degrees
T + C = 110 degrees, and T=C (according to the definition of an isosceles triangle).
measure of T is 110/2 which equals 55 degrees

3 0

3 years ago

Read 2 more answers

Activity

hodyreva [135]

Answer:

The answers to each part are:

Part A.

The quantity of apples is one-third of the quantity of grapes.

Part B.

The quantity of apples is a quarter of the quantity of strawberries.

Part C.

The number of cherries is two-elevenths of the total fruit.

Step-by-step explanation:

To identify the answer in each case, you must remember that all the parts are equal, then:

Part A.

The parts of apples are 1 and the parts grapes are 3, so if you divide the first quantity with the second quantity you obtain:

1 / 3 = 1/3 (one-third)

So, the quantity of apples is one-third of the quantity of grapes or the quantity of apples is three times smaller than the quantity of grapes.

Part B.

The parts of apples are 1 and the parts of strawberries are 4, then you must divide the first quantity with the second quantity:

1 / 4 = 1/4 (a quarter)

In this case, the quantity of apples is a quarter of the quantity of strawberries or the quantity of apples is four times smaller than the quantity of strawberries.

Part C.

First, you must add all the part of fruit:

1 part apple
1 part orange
4 parts strawberry
2 parts cherry
3 parts grape

The total of fruits is 11 parts, taking into account the quantity of cherries is 2, now you can divide the number of cherries with the total parts of fruit:

2 / 11 = 2/11 (two-elevenths)

Now, you can see the number of cherries is two-elevenths of the total fruit.

3 0

3 years ago