Find the lowest common denominator of p+3/p^2+7 p+10 and p+5/p^2+5 p+6
2 answers:
We first need to factorize (if possible) the denominators:
we can see that
as 2 and 5 are two numbers whose sum is 7 and product is 10.
Similarly, we can see that
as 2 and 3 are two numbers whose sum is 5 and product is 6.
Thus, the expression is:
.
Now to make the denominators equal, but to also keep them as small as possible, the common denominator must be (p+3)(p+2)(p+5).
Answer: (p+3)(p+2)(p+5).
we can see that
Similarly, we can see that
Thus, the expression is:
Now to make the denominators equal, but to also keep them as small as possible, the common denominator must be (p+3)(p+2)(p+5).
Answer: (p+3)(p+2)(p+5).
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Answer:
k = 9
Step-by-step explanation:
Consider the pattern on the right side , that is
= k(k + 2) + 1 = k² + 2k + 1
Equating
k² + 2k + 1 = 100 ( subtract 100 from both sides )
k² + 2k - 99 = 0 ← in standard form
(k + 11)(k - 9) = 0 ← in factored form
Equate each factor to zero and solve for k
k + 11 = 0 ⇒ k = - 11
k - 9 = 0 ⇒ k = 9
But k > 0 , then k = 9