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inessss [21]
3 years ago
7

Help plz i kind of get it but i want clarification

Mathematics
1 answer:
Alenkinab [10]3 years ago
3 0
We can't see the attachment 

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Solving equations and Inequalities 1 ) -10p=2(p-12)
MArishka [77]
The answer is 2 = p
Explanation: Here the goal is to get the variable "p" by itself, so first your have to distribute 2 to (p-12) which gives you -10p = 2p-24. Then you add 10p on both sides so that the variable is on one side. Then you add 24 to both sides. After that you divide 12 from both sides, giving you 2 = P

-10P = 2(p-12)
-10p = 2p-24
+10p +10p
0 = 12p-24
+24 +24
24 = 12p
24÷12 = 12p÷12
2 = p
5 0
3 years ago
F(x)=x^2 what is g(x)
AysviL [449]
Is C g(x) = -X^2 -3

This is the answer
4 0
3 years ago
A single die is rolled. Find the probability of rolling and odd number or a number less than 4
sweet [91]
6 sides on a dice 1-6 numbers probability is 4/6 or 2/3
3 0
3 years ago
According to a study done by Wakefield Research, the proportion of Americans who can order a meal in a foreign language is 0.47.
UNO [17]

Answer:

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

Step-by-step explanation:

We are given that according to a study done by Wake field Research, the proportion of Americans who can order a meal in a foreign language is 0.47.

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language.

<em>Let </em>\hat p<em> = sample proportion of Americans who can order a meal in a foreign language</em>

The z-score probability distribution for sample proportion is given by;

          Z = \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion

p = population proportion of Americans who can order a meal in a foreign language = 0.47

n = sample of Americans = 200

Probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is given by = P( \hat p > 0.50)

  P( \hat p > 0.06) = P( \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } > \frac{0.5-0.47}{\sqrt{\frac{0.5(1-0.5)}{200} } } ) = P(Z > 0.85) = 1 - P(Z \leq 0.85)

                                                               = 1 - 0.80234 = <u>0.19766</u>

<em>Now, in the z table the P(Z  </em>\leq <em>x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.85 in the z table which has an area of 0.80234.</em>

Therefore, probability that the proportion of Americans who can order a meal in a foreign language is greater than 0.5 is 0.19766.

4 0
3 years ago
6.3 covert to fractional form like a fraction and get a like and brainiest !
Lina20 [59]
Fractional form: 63/10 or 6 3/10.
8 0
3 years ago
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