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3 years ago

PLEASE HELP!! DUE SOON!!! WILL GIVE 5 STARS ALONG WITH A HEART!!!

Mathematics

1 answer:

kvasek [131]3 years ago

7 0

Answer:

Step-by-step explanation:

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The client is to receive cyclophosphamide (Cytoxan) 50 mg/kg intravenously in divided doses over 5 days. The client weighs 176 p

marishachu [46]

Answer:

800 mg

Step-by-step explanation:

As the excerpt states that the client weights 176 pounds and is to receive cyclophosphamide (Cytoxan) 50 mg/kg, we have to convert 176 pounds to kg:

1 kg → 2.20 pounds

x ← 176 pounds

x= (176 pounds * 1 kg)/2.20 pounds= 80 kg

Now, we have to determine the total amount of cyclophosphamide (Cytoxan) that the client has to receive:

50 mg/kg

For 80 kg: 80 kg *50 mg/kg= 4,000 mg

As the dose is divided over 5 days:

4,000 mg / 5= 800 mg

The client will receive 800 mg of cyclophosphamide each day.

6 0

3 years ago

Simplify: 9 x 5 ( 2 x 4 )

amid [387]

Is it 360 or 53 I think it’s 360

5 0

3 years ago

Read 2 more answers

What is the perimeter of a rectangle with length x+4 and a width of 5x-7

AlladinOne [14]

Answer:

12x-6

Step-by-step explanation:

perimeter= 2l+2w

=2(x+4)+2(5x-7)

=2x+8+10x-14

=12x-6

8 0

3 years ago

A frightened child is restrained by her mother as the child slides down a frictionless playground slide. If the force on the chi

MissTica

Answer:

Step-by-step explanation:

Given

Restrained Force $F=116 N$

Increase in Kinetic Energy $\Delta K.E.=30 J$

Distance moved d=1.9 m

Work done by all the forces is equal to change in Kinetic Energy of Object i.e. by gravity force, Normal force and Applied Force

$\Delta K.E.=W_g+W_f+W_N$

$30=W_g-F\cdot d$

$30=W_g-116\cdot 1.9$

$W_g=250.4 J$

(b)In absence of applied force thus

work done by gravity will be equal to change in kinetic Energy

change in Kinetic Energy $=210 J$

6 0

4 years ago

Write your own explicit formula. List the first 4 terms and solve for the 10th term using the formula. (show your work)

Shalnov [3]

Answer:

See below.

Step-by-step explanation:

Formula:

$a_n = 3(n + 4)$

First term: n = 1

$a_1 = 3(1 + 4) = 15$

Second term: n = 2

$a_2 = 3(2 + 4) = 18$

Third term: n = 3

$a_3 = 3(3 + 4) = 21$

Fourth term: n = 4

$a_4 = 3(4 + 4) = 24$

Tenth term: n = 10

$a_{10} = 3(10 + 4) = 42$

4 0

3 years ago