Answer:
A normal model is a good fit for the sampling distribution.
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
The standard deviation of this sampling distribution of sample proportion is:
The information provided is:
<em>N</em> = 675
<em>X</em>₁ = bodies with low vitamin-D levels had weak bones
<em>n</em>₁ = 82
<em>p</em>₁ = 0.085
<em>X</em>₂ = bodies with regular vitamin-D levels had weak bones
<em>n</em>₂ = 593
<em>p</em>₂ = 0.01
Both the sample sizes are large enough, i.e. <em>n</em>₁ = 82 > 30 and <em>n</em>₂ = 593 > 30.
So, the central limit theorem can be applied to approximate the sampling distribution of sample proportions by the Normal distribution.
Thus, a normal model is a good fit for the sampling distribution.
Answer:
the answer is
Step-by-step explanation:
Answer:
The second, 16^3/2
Step-by-step explanation:
The first is equal to 16
The second is equal to 64
The third is equal to 16
The fourth is equal to 16
Answer:
x
=
1
+
3
i
,
1
−
3
i
Step-by-step explanation:
Answer: Change 4.62 to 462.
Step-by-step explanation: If you multiply 4.62 by 100 you get 462.
1) 46/6 = 7 r 4
2) Drop down the 2 and 42/6 equals 7.
3) This will make each person get 77.
Answer: 77
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