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Kruka [31]
3 years ago
9

U WILL BE MARKED BRAINLIST IF CORRECT

Mathematics
2 answers:
blagie [28]3 years ago
7 0

Answer:

The answer on khan academy is C. None of the above.

Step-by-step explanation:

djyliett [7]3 years ago
6 0
If im right i think is A
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A number is between -2 and -10. What is the least possible integer value of this number
astraxan [27]
-9, it is between -2 and -10 and it is the least possible integer
6 0
3 years ago
WILL GIVE BRAINLEST!!! solve the triangle and answers to the nearest tenth.
sineoko [7]

Answer:

Angle A is 29 degress Angle B is 61 Angle C is 90

Side AB is 5.8 Side BC is 2.8 and  Side AC is 5.1

Step-by-step explanation:

Angle A is found using triangle interior theorem.

I found side AC by using law of sines

b/sin b= c/sin c

x/sin 61= 5.8/sin 90( which equal 1)

x=5.1

I found side BC by using pythagoren theorem.

a^2 + b^2=c^2

5.1^2+ b^2=5.8^2

26.01+b^2=36.64

b^2=7.63

b=approx 2.8.

8 0
3 years ago
Find the inverse of f(x)=1/(x^3)
Pepsi [2]

Answer:

Step-by-step explanation:

yf(x)^{-1}  = inverse\\f(x)=y \\y = 1/(x^{3} \\Inverse: y=x ------------> x = 1/y^{3}\\y^{3} - \frac{1}{x} = 0\\y^{3} = \frac{1}{x}\\y = \sqrt[3]{\frac{1}{x}} \\y = \frac{\sqrt[3]{1} }{\sqrt[3]{x}} \\y = \frac{1}{\sqrt[3]{x}}

4 0
3 years ago
Given that the expression x³_ ax² + bx+c leaves the same remainder when divided by x + 1 or x-2, find 'a' in terms of 'b'.​
goblinko [34]

Answer:

Hi,

a=b+3

Step-by-step explanation:

\begin{array}{c||c|c|c|c}&x^3&x^2&x&1\\---&---&---&---&---\\&1&-a&b&c\\x=-1&&-1&a+1&-a-b-1\\---&---&---&---&---\\&1&-a-1&a+b+1&c-a-b-1\\\end{array}

\begin{array}{c||c|c|c|c}&x^3&x^2&x&1\\---&---&---&---&---\\&1&-a&b&c\\x=2&&2&4-2a&2b+8-4a\\---&---&---&---&---\\&1&2-a&b+4-2a&c+2b+8-4a\\\end{array}

Thus:

c+2b+8-4a=c-a-b-1

3b-3a=-9

<u>a=b+3</u>

5 0
2 years ago
at fish world,clownfish are on sale for $5 off with a maximum of 6 fish per customer. Rudy buys 6 clownfish on sale plus 3 more
ICE Princess25 [194]
I’m sorry but I don’t know i would honestly like to help u but don’t know
6 0
3 years ago
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