3 years ago

U WILL BE MARKED BRAINLIST IF CORRECT

Mathematics

2 answers:

blagie [28]3 years ago

7 0

Answer:

The answer on khan academy is C. None of the above.

Step-by-step explanation:

djyliett [7]3 years ago

6 0

If im right i think is A

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A toy manufacturer wants to know how many new toys children buy each year. A sample of 601 children was taken to study their pur

Lilit [14]

Answer:

The confidence interval is 6.6<μ<6.8.

Step-by-step explanation:

We have:

Number of observations = 601

Mean = 6.7

Standard deviation σ = 1.5

The z-score for a 95% confidence interval is 1.96.

The limits of the confidence interval can be calculated as

$X \pm z*\frac{\sigma}{\sqrt{n}}\\\\LL=X-z*\frac{\sigma}{\sqrt{n}}=6.7-1.96*\frac{1.5}{\sqrt{601} } =6.7-0.1199=6.6\\\\UL=X+z*\frac{\sigma}{\sqrt{n}}=6.7+1.96*\frac{1.5}{\sqrt{601} } =6.7+0.1199=6.8$

The confidence interval is 6.6<μ<6.8.

7 0

4 years ago

What is the mathematical induction of <br> 1+3+5+...+(2n-1)=n^2

Lena [83]

Let $S(n)$ be the statement that

$1+3+5+\cdots+(2n-1)=\displaystyle\sum_{k=1}^n(2k-1)=n^2$

Check to see that $S(n)$ holds for $n=1$ :

$\displaystyle\sum_{k=1}^1(2k-1)=1=1^2\implies S(1)\text{ is true}$

Now suppose that $S(N)$ is true, and use that assumption to show that $S(N+1)$ must also be true. When $n=N+1$ , you have

$\displaystyle\sum_{k=1}^{N+1}(2k-1)=\sum_{k=1}^N(2k-1)+2(N+1)-1$
$=N^2+2(N+1)-1$
$=N^2+2N+1$
$=(N+1)^2$

and so $S(N+1)$ is also true, thus proving the statement is true for all $n$ .