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3 years ago

Which solution causes cells to shrink

1 answer:

7 0

Answer: Hypertonic

Explain: a hypertonic solution has increased solute and a net movement of water outside causing the cell to shrink. A hypotonic has decreased solute concentration, and a net movement of water inside the cell, causing swelling or breakage.

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Design a logic circuit that has a 4-bit binary number as an input and one output. The output should be 1 iffthe input is a prime

Maurinko [17]

Answer:

Check the explanation

Explanation:

Solution

Let the $L_1$ binary input one A,B,C,D and output is F with $L_1$ binary inputs we have $16=2^4$ combination as in below.

Kindly check the attached image below to get the full step by step explanation to the question above.

5 0

4 years ago

Water is the working fluid in an ideal Rankine cycle. Steam enters the turbine at 1400 lbf/in2 and 1000°F. The net power output

Alex17521 [72]

Answer:

(a) The mass flow rate of the steam is approximately 1.803×10⁶ lb/h

(b) The rate of heat transfer is approximately 2.52×10⁹ BTU/h

(d) The mass flow rate of cooling water is approximately 9.478 × 10⁷ lb/h

Explanation:

(a) The parameters are;

T₁ = 1000 F, P₁ = 1400 psi

By using an online application, we have;

h₁ = 1494 BTU/lb = 3,475 kJ/kg

s₁ = 1.61 BTU/(lb·R) = 6.741 kJ/(kg·K)

Therefore, due to isentropic expansion from state 1 to state 2, we have;

s₁ = s₂ = 1.61 BTU/(lb·R)

P₂ = 2 psi

T₂ =

$s_f$ = 0.17498 BTU/(lb·R)

$h_{f2}$ = 94.02 BTU/(lb)

$h_g$ = 1116 BTU/lb

$s_g$ = 1.919 BTU/(lb·R)

We have;

x₂ = (1.61 - 0.17498)/(1.919 - 0.17498) ≈ 0.823

h₂ = $h_f$ + x₂×( $h_g$ -

P₃ = P₂ = 2 psi

h₃ = $h_{f2}$ = 94.02 BTU/(lb)

v₃ = 0.01605 ft³/lb

h₄ = h₃ + v₃ × (P₄ - P₃)

h₄ = 94.02 + 0.01605 × (1400 - 2) ×144/778 = 98.17 BTU/lb

The mass flow rate of the steam, $\dot m$ = $\dot W$ /((h₁ - h₂) - (h₄ - h₃)) = 1 * 10^9/((1494 -935.11) - (98.17 -94.02)) ≈ 1.803×10⁶ lb/h

$\dot m$ ≈ 1.803×10⁶ lb/h

The mass flow rate of the steam ≈ 1.803×10⁶ lb/h

(b)The rate of heat transfer, $\dot Q_{in}$ = $\dot m$ × (h₁ - h₄) = 1.803×10⁶×(1494 -98.17) ≈ 2.52×10⁹ BTU/h

$\dot Q_{in}$ ≈ 2.52×10⁹ BTU/h

The thermal efficiency ≈ 39.68%

(d) The mass flow rate of cooling water $\dot m_w$ = $\dot m$ (h₂- h₃)/( $c_w \Delta T$ )

$c_w$ = 1 BTU/(lb·°F)

$\dot m_w$ = 1.803×10⁶ (935.11- 94.02)/(1 * (76 - 60)) ≈ 9.478 × 10⁷ lb/h

$\dot m_w$ ≈ 9.478 × 10⁷ lb/h

The mass flow rate of cooling water ≈ 9.478 × 10⁷ lb/h.

5 0

3 years ago

Hello good morning have a great day

Romashka [77]

Answer:

good morning have a great day

8 0

3 years ago

What do you do if building doesn't have enough water pressure for sprinklers? a. Increase pipe size b. Adjust budget to accommod

yulyashka [42]

Explanation:

the condition of education adda

5 0

3 years ago

A Carnot cooler operates with COP = 11, whose ambient temperature is 300K. Determine the temperature at which the refrigerator a

SashulF [63]

Answer:

275 Kelvin

Explanation:

Coefficient of Performance=11

$T_H=\text {Absolute Temperature of high temperature reservoir=300 K}$

$T_L=\text {Absolute Temperature of low temperature reservoir}$

$\text {Coefficient of performance for carnot cooler}\\=\frac {T_L}{T_H-T_L}\\\Rightarrow 11=\frac{T_L}{300-T_L}\\\Rightarrow 11(300-T_L)=T_L\\\Rightarrow 3300-11T_L=T_L\\\Rightarrow 3300=T_L+11T_L\\\Rightarrow 3300=12T_L\\\Rightarrow T_L=\frac {3300}{12}\\\Rightarrow T_L=275\ K\\\Therefore \text{Temperature at which the refrigerator absorbs heat=275 Kelvin}$

8 0

3 years ago