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schepotkina [342]
2 years ago
14

Deidre has just moved from the sales department into the finance department. On her first day in her new role, she receives an e

-mail with a list of systems that she should become familiar with. She tries to access the first system on the list and gets an access denied error message. Which of the following is the most likely reason why?
a. The certificate associated with her account has expired.
b. Her user account's password coincidentally has expired.
c. Her account has been locked due to too many failed login attempts.
d. The company uses role-based access control and her user account hasn't been migrated into the correct group(s) yet.
Engineering
1 answer:
melisa1 [442]2 years ago
3 0

Answer:

 d. The company uses role-based access control and her user account hasn't been migrated into the correct group(s) yet

Explanation:

Since Deidre is accessing her e-mail there appears to be nothing wrong with her account or password. Since her role is new, most likely the problem is associated with her new role.

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The author states that chemical engineering is one of the most difficult and complex aspects of engineering. Why do you think th
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Answer:

hope this helps

Explanation:

answers:

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8 0
3 years ago
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A fluid of density 900 kg/m3 passes through a converging section of an upstream diameter of 50 mm and a downstream diameter of 2
NISA [10]

Answer:

Q= 4.6 × 10⁻³ m³/s

actual velocity will be equal to 8.39 m/s

Explanation:

density of fluid = 900 kg/m³

d₁ = 0.025 m

d₂ = 0.05 m

Δ P = -40 k N/m²

C v = 0.89

using energy equation

\dfrac{P_1}{\gamma}+\dfrac{v_1^2}{2g} = \dfrac{P_2}{\gamma}+\dfrac{v_2^2}{2g}\\\dfrac{P_1-P_2}{\gamma}=\dfrac{v_2^2-v_1^2}{2g}\\\dfrac{-40\times 10^3\times 2}{900}=v_2^2-v_1^2

under ideal condition v₁² = 0

v₂² = 88.88

v₂ = 9.43 m/s

hence discharge at downstream will be

Q = Av

Q = \dfrac{\pi}{4}d_1^2 \times v

Q = \dfrac{\pi}{4}0.025^2 \times 9.43

Q= 4.6 × 10⁻³ m³/s

we know that

C_v =\dfrac{actual\ velocity}{theoretical\ velocity }\\0.89 =\dfrac{actual\ velocity}{9.43}\\actual\ velocity = 8.39m/s

hence , actual velocity will be equal to 8.39 m/s

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