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noname [10]
3 years ago
11

In order to keep a specific bacteria alive, the tempature in a science lab, cannot exceed -20F. The electricity went out, when t

he tempature was -72F, but is increasing at a rate of 6.5 per hour. How many hours do the scientist have until the bacteria is not safe?
Mathematics
1 answer:
Vladimir [108]3 years ago
3 0

Answer:

At most 8 hours

Step-by-step explanation:

Given

Maximum = -20F

Rate = 6.5/hour

Base\ Temperature =-72F

Required

Determine the time taken

Represent time by t.

The relationship between all parameters is:

Maximum = Base\ Temperature + Rate * t

Base\ Temperature + Rate * t \leq Maximum

This is so (≤) because, according to the question, the temperature can not exceed the maximum.

So, we have:

-72 + 6.5*t \leq -20

-72 + 6.5t \leq -20

Collect Like Terms

6.5t \leq -20 + 72

6.5t \leq 52

Solve for t

t \leq 52/6.5

t \leq 8

<em>Hence, they have at most 8 hours</em>

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Assuming that <em>a + 2 = y</em>, the property that was applied to arrived at <em>(a + 2)/3 = y/3</em> is the: division property of equality.

<em><u>Recall:</u></em>

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Learn more here:

brainly.com/question/13260378

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