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3 years ago

What expressions are equivalent to 1/5•1/5•1/5•1/5

Mathematics

2 answers:

Luden [163]3 years ago

8 0

C because if you put them both in the calculator they are the same

Over [174]3 years ago

5 0

Answer:

Step-by-step explanation: Because equivalent expressions is when you Combine any like terms on each side of the equation: x-terms with x-terms and constants with constants. Arrange the terms in the same order, usually x-term before constants. If all of the terms in the two expressions are identical, then the two expressions are equivalent.

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four students get 90s on a test. three get 70s 2 get 60s and one gets an 80. What is the mean test score in this group

ehidna [41]

Its 85-90 hope this helps :)

4 0

4 years ago

Cindy plants a daffodil plant. If the plant has one daffodil flower to start with, and the number of daffodils triples every wee

Romashka [77]

Answer:

There will be 729 daffodils in the sixth week

Step-by-step explanation:

Given

$a = 1$ --- start

$r = 3$ --- weekly rate

Required

Number of daffodils in 6th week

This question illustrates an exponential function which is represented as

$f(x) = ab^x$

Where

f(x) = Number of daffodils at x week

x = The week

a = Initial number of daffodils

b= rate

So, we have:

$a = 1$

$b = r = 3$

Hence:

$f(x) = 1 * 3^x$

$f(x) = 3^x$

At the 6th week

$x = 6$

So:

$f(6) = 3^6$ <em> ---- as a power</em>

$f(6) = 3 * 3 * 3 * 3 * 3 * 3$ <em> --- related multiplication</em>

$f(6) = 729$ <em> --- standard form</em>

4 0

3 years ago

The length of an object is measured as 84.8 centimeters. What is this measurement in scientific notation

Misha Larkins [42]

8.48 multiplied by 10 to the power of one

3 0

4 years ago

Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2

Anastaziya [24]

Answer:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

Step-by-step explanation:

we would like to figure out the derivative of the following:

$\displaystyle \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

to do so, let,

$\displaystyle y = \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }$

By simplifying we acquire:

$\displaystyle y = 3 - \frac{2}{x} - \frac{1}{ {x}^{2} }$

use law of exponent which yields:

$\displaystyle y = 3 - 2 {x}^{ - 1} - { {x}^{ - 2} }$

take derivative in both sides:

$\displaystyle \frac{dy}{dx} = \frac{d}{dx} (3 - 2 {x}^{ - 1} - { {x}^{ - 2} } )$

use sum derivation rule which yields:

$\rm\displaystyle \frac{dy}{dx} = \frac{d}{dx} 3 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

By constant derivation we acquire:

$\rm\displaystyle \frac{dy}{dx} = 0 - \frac{d}{dx} 2 {x}^{ - 1} - \frac{d}{dx} {x}^{ - 2}$

use exponent rule of derivation which yields:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ - 1 -1} ) - ( - 2 {x}^{ - 2 - 1} )$

simplify exponent:

$\rm\displaystyle \frac{dy}{dx} = 0 - ( - 2 {x}^{ -2} ) - ( - 2 {x}^{ - 3} )$

two negatives make positive so,

$\displaystyle \frac{dy}{dx} = 2 {x}^{ -2} + 2 {x}^{ - 3}$

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

$\displaystyle \frac{dy}{dx} = \frac{2 }{x^2}+ \frac{2}{x^3}$

simplify addition:

$\displaystyle \frac{dy}{dx} = \frac{2x + 2}{x^3}$

and we are done!

5 0

3 years ago

You went out for dinner with your family. The bill was $160 and your family left a

Dvinal [7]

Answer:192$

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers