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artcher [175]
3 years ago
14

Question 7

Chemistry
1 answer:
Aneli [31]3 years ago
4 0
D =temperature of the water
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Need help asap! A 200 L balloon is blown up inside at 100 K. It is then taken outside in the hot sun and heated to 400K. What is
liq [111]
<h2>Answer</h2>

The volume will be<u> 50 L</u>

<h2>Explanation</h2>

From Kelvin Law of Temperature, we know that

V_{1} T_{1} =V_{2} T_{2}

We know that

V_{1} = 200 L

T_1 = 100 K

T_2= 400 K

So,

V_{2} = V_{1} T_{1}/T_{2}

V_{2} = 200*100/400

V_{2} = 50 L

The answer of the givern question is 50L


5 0
4 years ago
Read 2 more answers
This element has 80 electrons and is considered a transitional element. What am I?
sdas [7]

Answer:its mercury i think!!!!!

Explanation:

8 0
3 years ago
What is the correct name for CaS04? (a) calcium sulfoxide (b) calcium sulfite (c) calcium sulfur oxide (d) calcium sulfate (e) c
Zielflug [23.3K]

Answer: OPTION, D

Explanation:

It is an example for ionic salt and has Calcium ion and sulfate ion.

Hence it's name is Calcium sulfate.

Calcium sulfoxide does not exist.

Calcium sulfite has CaSO3.

5 0
3 years ago
Read 2 more answers
How many grams of H2SO4 are needed to prepare 500. mL of a .250M solution?
zavuch27 [327]

Answer:

We need 12.26 grams H2SO4

Explanation:

Step 1: Data given

Volume of a H2SO4 solution = 500 mL = 0.500 L

Concentration of the H2SO4 solution = 0.250 M

Molar mass of H2SO4 = 98.08 g/mol

Step 2: Calculate moles H2SO4

Moles H2SO4 = concentration * volume

Moles H2SO4 = 0.250 M * 0.500 L

Moles H2SO4 = 0.125 moles

Step 3: Calculate mass of H2SO4

Mass of H2SO4 = moles * molar mass

Mass of H2SO4 = 0.125 moles * 98.08 g/mol

Mass of H2SO4 = 12.26 grams

We need 12.26 grams H2SO4

7 0
3 years ago
1 kg of water (specific heat = 4184 J/(kg K)) is heated from freezing (0°C) to boiling (100°C). What is the change in thermal en
Andrews [41]

Answer: 1560632 joules

Explanation:

The change in thermal energy (Q) required to heat ice depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = ?

Mass of frozen water (ice) = 1kg

C = 4184 J/(kg K)

Φ = (Final temperature - Initial temperature)

= 100°C - 0°C = 100°C

Convert 100°C to Kelvin

(100°C + 273) = 373K

Then, Q = MCΦ

Q = 1kg x 4184 J/(kg K) x 373K

Q = 1560632 joules

Thus, the change in thermal energy is 1560632 joules

5 0
4 years ago
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