Answer:
57.39
[tex]440 \: ( 1 + \frac{5t}{46 + \: {t}^{2} } ) \\ 440 \: ( \frac{6t}{46 {t}^{2} } ) \: ( \: multiply \: 440 \times 6t) \\ \frac{2640}{46} \\ = 57.39 or 57.30
Answer:
(- 4, - 12 ) , (4, 12 )
Step-by-step explanation:
Given the 2 equations
y = 3x → (1)
y = x² + 3x - 16 → (2)
Substitute y = x² + 3x - 16 into (1)
x² + 3x - 16 = 3x ( subtract 3x from both sides )
x² - 16 = 0 ( add 16 to both sides )
x² = 16 ( take the square root of both sides )
x = ±
= ± 4
Substitute these values into (1) for corresponding values of y
x = - 4 : y = 3 × - 4 = - 12 ⇒ (- 4, - 12 )
x = 4 : y = 3 × 4 = 12 ⇒ (4, 12 )
<span>The original statement would remove the two "not" values from the converse, giving "If it is April 17th, then it is Matt's birthday." Similarly, to find the inverse of the original conditional, simply flip the two statements. As such, the inverse would read "If it is Matt's birthday, then it is April 17th."</span>
It has no solution because it is not factorable
Stop copying the question, it's confusing
so 100 cookies and 20 brownies
what is the greatest number you can divide them both by?
find the GCF
factor them
100=2*2*5*5
20=2*2*5
so the GCF is the common group to both or 2*2*5 or 20
100/20=5
20/20=1
there are 20 groups, each wit 5 cookies and 1 brownie
20 groups