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3 years ago

A cylindrical syringe has a height of 6.8 cm and a diameter of 2.37 cm is going to be

Mathematics

1 answer:

alukav5142 [94]3 years ago

7 0

Answer:

The number of syringe filled with water that would be needed to fill the semi-sphere is approximately 8.714 syringes

Step-by-step explanation:

The height of the syringe = 6.8 cm

The diameter of the syringe = 2.37 cm

The circumference of the hemisphere = 31.4 cm

Let r represent the radius of the hemisphere, we have;

2·π·r = 31.4 cm

r = 31.4/(2 × π) ≈ 4.9975 cm

The volume of the hemisphere = 2/3 × π × r³ = 2/3 × π × (31.4/(2 × π))³ ≈ 261.4 cm³

The volume of the syringe = π × d²/4 × h = π × 2.37²/4 × 6.8 ≈ 29.998 cm³

The number of syringe filled with water that would be needed to fill the semi-sphere = (The volume of the hemisphere)/(The volume of the syringe)

Therefore;

The number of syringe filled with water that would be needed to fill the semi-sphere = 261.4 cm³/(29.998 cm³) ≈ 8.714 syringes.

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kogti [31]

Answer: 110/3

Step-by-step explanation:

5x+15= 8x+2 = 13/3

5 * 13/3 + 15= 110/3

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3 years ago

For what value of the variable will b the value of 3−5c be 1 less than the value of 1−c?

Crank

Answer:

c = 3/4

Step-by-step explanation:

Lets set up an equation.

You can get

3-5c + 1 = 1-c to show that it is one less.

now we can solve it.

So by combining like terms, we get:

4-5c = 1-c

that then becomes:

3-5c = -c

--> 3 = 4c

--> c = 3/4

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3 years ago

The area of a square is defined by, A(x) = x 2 - 12x + 36. What is the length of a side of the square?

kumpel [21]

A(x) = x 2 - 12x + 36
A(x) = (x -6)^2

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3 years ago

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NARA [144]

Answer:

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Step-by-step explanation:

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2 years ago

Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)

PtichkaEL [24]

Answer:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

Step-by-step explanation:

$(x^{3} x^{-6} )^{2}$ is the expression given to be solved.

First of all let us have a look at 3 formulas:

$1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}$

Both the formula can be applied to the expression( $(x^{3} x^{-6} )^{2}$ ) during the first step while solving it.

Applying formula (1):

$(x^{3} x^{-6} )^{2}$

Comparing the terms of $(x^{3} x^{-6} )$ with $p^a \times p^b$

$p=x, a =3, b=-6$

$\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $(x^{-3} )^{2}$

Applying formula (2):

Comparing the terms of $(x^{3} x^{-6} )^{2}$ with $(p^a \times q^b)^c$

$p=q=x, a =3, b=-6, c=2$

$\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $x^6 x^{-12}$ .

So, the answers can be:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

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3 years ago