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snow_tiger [21]
4 years ago
12

F(x)=2(x-4)(x+1) how do i convert this factored form to standard form?

Mathematics
1 answer:
zhenek [66]4 years ago
5 0

I'd would do the FOIL method and then distribute the 2. But you can also distribute first. Either way, they want you to expand it.

(x - 4)(x + 1) = x(x) + x(1) - 4(x) - 4(1)

Simplify

x² + 1x - 4x - 4

Combine like terms:

x² - 3x - 4

Now, bring back that 2 to distribute.

2(x² - 3x - 4) = 2(x²) + 2(- 3x) + 2(- 4)

f(x) = 2x² - 6x - 8

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Raina must choose a number between 55 and 101 that is a multiple of 2, 8 and 10. Write all the numbers that she could choose. If
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Answer:

The only possible number is 80.

Step-by-step explanation:

The number in question needs to be a multiple of all three of 2, 8, and 10. As a result, it must also be a multiple of the least common multiplier (lcm) of the three number.

Start by finding the least common multiplier of the three numbers.

Factor each number into its prime components:

  • 2 is a prime number itself.
  • 8 = 2^3.
  • 10 = 2 \times 5.

The only prime factors are 2 and 5.

  • The greatest power of 2 among the three numbers is 3.
  • The greatest power of 5 among the three numbers is 1.

Therefore, the least common multiplier of the three number should be the product of 2^3 and 5. That's equal to 2^3 \times 5 = 8 \times 5 = 40.

In other words, the number (or numbers) in question could be written in the form 40\, k, where k is an integer.

The question requires that this number be between 55 and 101. In other words,

55 \le 40\, k \le 101.

The goal is to find the possible values of k. Note that from integer division by 40,

  • 55 = 1 \times 40 + 15, and
  • 101 = 2 \times 40 + 21.

The inequality becomes:

1 \times 40 + 15 \le 40\, k \le 2 \times 40 + 21.

However,

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Hence,

1 \times 40 < 1\times 40 + 15 \le 40\, k \le 2 \times 40 + 21 < 3 \times 40.

1 \times 40 < 40\, k < 3 \times 40.

Divide by the positive number 40 to obtain:

1 < k < 3.

Since k is an integers, k = 2.

Indeed, 40 \, k = 80 is between 55 and 101.

Therefore, 80 is the number in question.

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