Mike is traveling to the beach 30 miles away from his house. On Mike's

8_murik_8 [283]

Let, number of sold Pizza = x
Number of sold sub-sandwiches = x+13

So, equation would be: 6x + 4(x+13) = 262
6x + 4x+52 = 262
10x = 210
x = 210/10

x = 21 (Number of Pizza)
z+13 = 34 (Number of Sub-sandwiches)

Hope this helps!

7 0

4 years ago

What about 11 movie tickets

anygoal [31]

Answer:

Step-by-step explanation:

yes please

3 0

3 years ago

An obtuse angle measures 180 degrees.<br> always<br> sometimes<br> never

True [87]

Never,because obtuse angle is an angle measuring between 90 and 180
and if an angle measures 180 then it is a straight angle

7 0

3 years ago

Read 2 more answers

An assembly plant orders a large shipment of electronic circuits each month. The supplier claims that the population proportion

lara [203]

Answer:

$p_v =P(z>2.652)=0.0040$

So the p value obtained was a very low value and using the significance level assumed for example $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of defectives is significantly higher than 0.04.

Step-by-step explanation:

1) Data given and notation

n=300 represent the random sample taken

X=21 represent the number of defectives (value assumed)

$\hat p=\frac{21}{300}=0.07$ estimated proportion of defectives

$p_o=0.04$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion of defectives it's higher than 0.04.:

Null hypothesis: $p\leq 0.04$

Alternative hypothesis: $p > 0.04$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.07 -0.04}{\sqrt{\frac{0.04(1-0.04)}{300}}}=2.652$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.652)=0.0040$

So the p value obtained was a very low value and using the significance level assumed for example $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of defectives is significantly higher than 0.04.

8 0

3 years ago

Evaluate the exponential expression: (2x)2nd power −3y2nd power =___, if x = 5 and y = 3.

damaskus [11]

ANSWER

A. 73

EXPLANATION

The given expression is

$(2{x})^{2} - 3{y}^{2}$