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horsena [70]
3 years ago
10

Factor this equation 75k^2+30k=-3

Mathematics
2 answers:
Solnce55 [7]3 years ago
7 0

Answer:

k=-1/5

Step-by-step explanation:

Factor and set each factor equal to zero.

Add 3 to both sides of the equation.

75k^2+30k+3=0

Factor 3 out of 75k^2+30k+3.

Factor using the perfect square rule.

Divide each term by 3 and simplify.

Set the 5k+1 equal to 0.

Solve for k.

miskamm [114]3 years ago
5 0
The answer is K=-1/5

You suppose to divide both sides by 3.

Move the constant to the left-hand side and change its sign Use a^2 + 2 ab+ b^2 = (a+b)^2 to factor the expression.

The only way an exponentiation can be 0 is when the base equals 0.

Move the constant to the right-hand side and change its sign.

Divide both sides of the equation by 5.

Answer: K=-1/5

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Ratling [72]

Answer:

I would say the answer is 40 cookies

Step-by-step explanation:

The reason I say this is because if you write out the amount of cookies she can make with 6 cups of flour, you would get 30/6. 30 and 6 are both divisible by 6, so if you divided both by 6 you will get 5/1. 1 times 8 is 8, so if you multiply 5 by 8 you will get 40 cookies.

Hope this helped!

7 0
3 years ago
A cell phone plan charges a flat
torisob [31]

Answer:

1) c=.07h+15.25 is the answer.

7 0
2 years ago
Read 2 more answers
You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the
Otrada [13]

Answer:

Please check the explanation.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

7 0
3 years ago
Circle each number that is a solution of the given inequality.
mario62 [17]
C i think I’m not 100% sure
3 0
3 years ago
PLZ ANSWER THIS CORRECTLY FOR 100 POINTS AND BRANLIEST :DD
gavmur [86]

Actually Welcome to the Concept of the Angles,.

Since,the AE is a angle bisector, hence, BAE = EAC simply.

hence we equate them..

===> x+ 30 = 3x - 10

==> 3x - x = 30 + 10

==> 2x = 40

==> x = 20°

hence the major angle EAC = 3(20)-10 = 60-10 = 50°

hence, angle EAC = 50°

8 0
2 years ago
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