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mylen [45]
2 years ago
7

Write an exponential equation that represents the given situation. You invest $1000 and it increases 12% each year. Can you teac

h me it because i need to show my work, thank you
Mathematics
1 answer:
IrinaK [193]2 years ago
8 0

Answer:

FV= 1,000*(1.12^n)

Step-by-step explanation:

Giving the following information:

Initial investment= $1,000

Increase rate= 12% = 0.12

We need to formulate an exponential equation to show the value in n years.

<u>To calculate the Future Value, we need to use the following formula:</u>

FV= PV*(1+i)^n

Being:

FV= Future Value

PV= Initial Investment

i= increase rate

n= number of periods

FV= 1,000*(1.12^n)

<u>For example, for one year:</u>

FV= 1,000*(1.12^1)

FV= $1,120

For 3 years:

FV= 1,000*(1.12^3)

FV= $1,404.93

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36 > 9 > 7 > 0 > -3 > -132

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Answer:

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Step-by-step explanation:

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8 0
2 years ago
Simplify 2a^2b^3(4a^2+3ab^2-ab)
-BARSIC- [3]
2a^2b^3(4a^2+3ab^2-ab)=? 
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>

Substitute this back into the original equation and you get 
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) = 
<span>2a^3b^3(4a-b+3b^2)
</span>
3 0
3 years ago
The amount of time it takes Isabella to wait for the bus is continuous and uniformly distributed between 3 minutes and 17 minute
Arturiano [62]

Answer:

P(X>5) = 0.857

Step-by-step explanation:

Let X \sim uniform(3.17)

f(x) = \dfrac{1}{17-3}   ; \ \ \ 3 \le x \le 17

The required probability that it will take Isabella more than 5 minutes to wait for the bus can be computed as:

P(X > 5) =  \int ^{17}_{5} f(x) \ dx

P(X > 5) =  \int ^{17}_{5} \dfrac{1}{17-3} \ dx

P(X > 5) =\dfrac{1}{14}  \Big [x \Big ] ^{17}_{5}

P(X > 5) =\dfrac{1}{14} [17-5]

P(X > 5) =\dfrac{12}{14}

P(X>5) = 0.857

6 0
3 years ago
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