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mylen [45]
2 years ago
7

Write an exponential equation that represents the given situation. You invest $1000 and it increases 12% each year. Can you teac

h me it because i need to show my work, thank you
Mathematics
1 answer:
IrinaK [193]2 years ago
8 0

Answer:

FV= 1,000*(1.12^n)

Step-by-step explanation:

Giving the following information:

Initial investment= $1,000

Increase rate= 12% = 0.12

We need to formulate an exponential equation to show the value in n years.

<u>To calculate the Future Value, we need to use the following formula:</u>

FV= PV*(1+i)^n

Being:

FV= Future Value

PV= Initial Investment

i= increase rate

n= number of periods

FV= 1,000*(1.12^n)

<u>For example, for one year:</u>

FV= 1,000*(1.12^1)

FV= $1,120

For 3 years:

FV= 1,000*(1.12^3)

FV= $1,404.93

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3 years ago
PLEASE ANSWER! DESPERATE, DONT KNOW HOW TO DO IT!
Annette [7]

Answer:

a) x = -7

b) x = -3/2

c) x = -3/2

d) x = 2

e) x = -1

f) x = -2

g) x = 7/3

h) z = -18/5

i) x = 6

Explanation:

The are a couple of rules you should know first.

Negative exponent rule: a^{-x} = \frac{1}{a^{x}}

A negative exponent means the same thing as the positive exponent as a denominator under 1.

Exponent to another exponent: (a^{x})^{n}=a^{xn}

When raising an exponent to another exponent, you multiply the exponents.

Fraction as a base rule: (\frac{a}{b})^{x} = \frac{a^{x}}{b^{x}}

Apply the exponent to the numerator and denominator.

Base 1 rule: 1^{x} = 1

1 to the power of anything is 1.

Focus on exponents only: a^{x} = a^{n}\\x = n

If the bases are the same on both sides of the equation, you can solve for "x" in the exponent by focusing on it only.

Write as an exponent: Rewrite a normal number as an exponent instead. Example: 8=2^{3} or 125=5^{3}

Also, you need to know how to rearrange and simplify formulas to isolate variables (by doing reverse operations in reverse BEDMAS order).

Know how to use the distributive property with brackets, when you multiply each of the terms in the brackets with the term on the outside.

Use each of these rules to solve.

a) 2^{x+4} = \frac{1}{8}   Write 8 as exponent

2^{x+4} = \frac{1}{2^{3}}   Negative exponent rule

2^{x+4} = 2^{-3}   Focus on exponents only

x+4 = -3   Subtract 4 from each side to isolate

x = -3-4

x = -7

b) 9^{x}=\frac{1}{27}   Write 27 as exponent

9^{x}=\frac{1}{3^{3}}   Write 9 as exponent

(3^{2})^{x}=\frac{1}{3^{3}}   Exponent to another exponent

3^{2x}=\frac{1}{3^{3}}   Negative exponent rule

3^{2x}=3^{-3}   Focus on exponents only

2x=-3   Divide both sides by 2 to isolate

x=-\frac{3}{2}

c) 25^{x}=\frac{1}{125}   Rewrite 125 as exponent

25^{x}=\frac{1}{5^{3}}   Rewrite 25 as exponent

(5^{2})^{x}=\frac{1}{5^{3}}   Exponent to another exponent

5^{2x}=\frac{1}{5^{3}}   Negative exponent rule

5^{2x}=5^{-3}   Focus only exponents only

2x=-3   Divide both sides by 2 to isolate

x=-\frac{3}{2}

d)  7(3^{x})=63   Divide both sides by 7 to isolate

3^{x}=63/7

3^{x}=9   Write 9 as exponent

3^{x}=3^{2}   Focus on exponents

x=2

e) 10^{3x}=0.001   Write 0.001 as fraction

10^{3x}=\frac{1}{1000}   Write 1/1000 as exponent

10^{3x}=\frac{1}{10^{3}}   Neg. exponent

10^{3x}=10^{-3}   Focus on exponents

3x=-3   Divide both sides by -3

x=-3/3

x=-1

f) 6(\frac{1}{10})^{x}=600   Divide both sides by 6

(\frac{1}{10})^{x}=\frac{600}{6}

(\frac{1}{10})^{x}=100  Write 100 as exponent

(\frac{1}{10})^{x}=10^{2}   Fraction as base rule

\frac{1^{x}}{10^{x}}=10^{2}   Base 1 rule

\frac{1}{10^{x}}=10^{2}   Neg. exponent

10^{-x}=10^{2}   Focus on exponent

-x=2   Divide both sides by -1

x=-2

g) 27^{x-3}=(\frac{1}{3})^{2}   Write 27 as exponent

(3^{3})^{x-3}=(\frac{1}{3})^{2}   Exponent to another exponent

3^{3(x-3)}=(\frac{1}{3})^{2}   Fraction as base

3^{3(x-3)}=\frac{1^{2}}{3^{2}}   Base 1 rule

3^{3(x-3)}=\frac{1}{3^{2}}   Neg. exponent

3^{3(x-3)}=3^{-2}   Focus

3(x-3)=-2   Distribute over brackets

3x-9=-2   Add 9 to both sides

3x=-2+9

3x=7   Div. both sides by 3

x=\frac{7}{3}

h) 4^{\frac{2z}{3}} = 8^{z+2}   Write 4 as exponent

(2^{2})^{\frac{2z}{3}} = 8^{z+2}   Exponent to another exponent

2^{2\frac{2z}{3}} = 8^{z+2}   Write 8 as exponent

2^{2\frac{2z}{3}} = (2^{3})^{z+2}   Exponent to another exponent

2^{2\frac{2z}{3}} = 2^{3(z+2)}   Focus

2\frac{2z}{3} = 3(z+2)   Multiply whole number with fraction

\frac{4z}{3} = 3(z+2)   Distribute

\frac{4z}{3} = 3z+6   Multiply both sides by 3

4z = 3(3z+6)   Distribute

4z = 9z+18   Subtract 9z from both sides

4z-9z = 18

-5z = 18   Div. both sides by -5

z = -\frac{18}{5}

i) 5(2)^{x-1}+3=163   Subtract 3 on both sides

5(2)^{x-1}=163-3

5(2)^{x-1}=160   Div. both sides by 5

(2)^{x-1}=160/5

(2)^{x-1}=32   Write 32 as exponent

(2)^{x-1}=2^{5}   Focus

x-1=5   Add 1 to both sides

x=5+1

x=6

5 0
3 years ago
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