The bond between the N and 0 (double bond) transfers and gives a -ve charge on O and a +ve charge on N atom at the group . Thus the +vely charged nitrogen is electron-deficient pulling electrons towards itself!
The combination of the +vely charged nitrogen and the electronegative oxygen atom leads to delocalization causing the resonance effect.
Particles of gas are more scarcely placed as compared to that of liquid.
the intermolecular forces will be less in gaseous state and hence is less stable
Option C is the correct set of the problem for mass of water produced by 3.2 moles of oxygen and an excess ethene.
<h3>
Reaction between oxygen and ethene</h3>
Ethene (C2H4) burns in the presence of oxygen (O2) to form carbon dioxide (CO2) and water (H2O) along with the evolution of heat and light.
C₂H₄ + 3O₂ ----- > 2CO₂ + 2H₂O
from the equation above;
3 moles of O₂ ---------> 2(18 g) of water
3.5 moles of O₂ ----------> x
![x = 3.2 \times [\frac{2 \ moles \ H_2O}{3 \ moles \ O_2} ] \times[ \frac{18.02 \ g \ H_2O}{1 \ mole \ H_2O} ]](https://tex.z-dn.net/?f=x%20%3D%203.2%20%5Ctimes%20%5B%5Cfrac%7B2%20%5C%20moles%20%5C%20H_2O%7D%7B3%20%5C%20moles%20%5C%20O_2%7D%20%20%5D%20%5Ctimes%5B%20%5Cfrac%7B18.02%20%5C%20g%20%5C%20H_2O%7D%7B1%20%5C%20mole%20%5C%20H_2O%7D%20%5D)
Thus, option C is the correct set of the problem for mass of water produced by 3.2 moles of oxygen and an excess ethene.
Learn more about reaction of ethene here: brainly.com/question/4282233
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The number of mole of ethanol present in the beaker is 0.217 mole
Description of mole
The mole of a substance is related to it's mass and molar mass according to the following equation:
Mole = mass / molar mass
How to determine the mole of C₂H₅OH
From the question given above, the following data were obtained:
Mass of C₂H₅OH = 10 g
Molar mass of C₂H₅OH = (12×2) + (1.01×5) + 16 + 1.01 = 46.06 g/mol
Mole of C₂H₅OH =?
Mole = mass / molar mass
Mole of C₂H₅OH = 10 / 46.06
Mole of C₂H₅OH = 0.217 mole
Learn more about mole:
brainly.com/question/13314627#SPJ1
<span>bright yellow light and lots of heat-energy.</span>