Calculate the percentage of CL in AL(CLO3)3
1 answer:
Answer:
46.41%
Explanation:
Find the total r.m.m of AL(CLO3)3 put it equals to 100%.....The take 106.5,the total r.m.m of Cl and find the missing which is the percentage by cross multiplication
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If this is a true or false question then the answer is true.
Answer:
i think the answer is Continental polar air masses
Explanation:
C. 28 KJ AMU of H2O2 = 2(1) + 2(16) = 34 g/mol 10 g / 34 g/mol = 0.294 mol H2O2 0.294 mol / H = 2 mol / 190 KJ H = 28.9 KJ
Answer:
<u>27.3 L </u>
Explanation:
<u>Reaction</u>
N₂ (g) + 3H₂ (g) ⇒ 2NH₃ (g) This is the basic reaction at STP
<u>Solving</u>
10 g N₂ x 1 mol NH₃/28 g N₂ x 3 mol H₂/1 mole N₂ ⇒ 1.07 mol H₂
V = nRT/P [From Ideal Gas Equation] V = 1.07 x 62.36 x 298 K / 735 V = <u>27.3 L </u>
C funnel because the funnel would have a large enough entrance to put a solid through