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vazorg [7]
3 years ago
14

For the reaction H2SO4 + 2Na2OH4 —> Na2SO4 + 2H2O

Chemistry
1 answer:
beks73 [17]3 years ago
5 0
The answer is b) 12 i believe
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3 years ago
A solution contains 0.45 M hydrofluoric acid (HF; KA = 6.8 X 10−4). Write the dissociation reaction. Determine the degree of ion
Gala2k [10]

Answer:

Degree of ionization = 0.0377

pH of the solution = 1.769

Explanation:

Initial concentration of HF = 0.45 M

K_a = 6.8 \times 10^{-4}

                     HF \leftrightharpoons  H^+ + F^-

Initial        0.45                             0          0

At equi      0.45 - x                      x           x

Equilibrium constant = \frac{[H^+][F^-]}{HF}

                   6.8 \times 10^{-4}= \frac{[x][x]}{0.45 - x}

           x^2 + 6.8 \times 10^{-4} x -  6.8 \times 10^{-4} \times 4.5 = 0

x = 0.017 M

x = Cα

α = Degree of ionization

C = Concentration

Degree of ionization = \frac{0.017}{0.45} = 0.0377

pH = -log[H^+]

[H^+]=0.017 M

pH = -log[0.017]

             = 1.769

6 0
4 years ago
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